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Gala2k [10]
3 years ago
14

A water slide is constructed so that swimmers, starting from rest at the top of the slide, leave the end of the slide traveling

horizontally. As the drawing shows, one person hits the water 5.00 m from the end of the slide in a time of 0.270 s after leaving the slide. Ignore friction and air resistance, find the height H in the drawing.
Physics
1 answer:
solniwko [45]3 years ago
8 0

Answer:

17.86 m

Explanation:

The first step is to find the velocity of the swimmer.

Velocity, v = s/t

Velocity, v = 5 / 0.27

Velocity, v = 18.52 m/s

Then, we find the height

h = ½gt²

h = ½ * 9.8 * 0.27²

h = 4.9 * 0.0729

h = 0.36 m

Next, we apply the law of conservation of energy

mgH = mgh + ½ mv²

9.8Hm = m(9.8 * 0.36 + 0.5 * 18.52²)

9.8H = 3.528 + 171.4952

9.8H = 175.02

H = 175.02 / 9.8

H = 17.86 m

Therefore, the needed height is 17.86 m

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r-ruslan [8.4K]

Answer:

The resistance of the inductor at resonance is 258.76 ohms.

Explanation:

Given;

resistance of the resistor, R = 305 ohm

capacitance of the capacitor, C = 1.1 μF = 1.1 x 10⁻⁶ F

inductance of the inductor, L = 42 mH = 42 x 10⁻³ H = 0.042 H

At resonance the inductive reactance is equal to capacitive reactance.

\omega L = \frac{1}{\omega C}\\\\2\pi F_0 L =  \frac{1}{2\pi F_0 C}\\\\F_0 = \frac{1}{2\pi\sqrt{LC} }

Where;

F₀ is the resonance frequency

F_0 = \frac{1}{2\pi\sqrt{LC} } \\\\F_0 = \frac{1}{2\pi\sqrt{(0.024)(1.1*10^{-6})} }\\\\F_0 =980.4 \ Hz

The inductive reactance is given by;

X_l = 2\pi F_0 L\\\\X_l = 2\pi (980.4)(0.042) \\\\X_l = 258.76 \ ohms

Therefore, the resistance of the inductor at resonance is 258.76 ohms.

5 0
3 years ago
Which of the following statements are correct? 1. Electrons and protons have identical masses but opposite charges. 2. Most of a
lisabon 2012 [21]

Answer:

b 2 only

Explanation:

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Atoms do not always have the same number of neutrons and protons. For, example ¹³C has 6 protons and 7 neutrons.

Atoms do have most of the mass concentrated at the center called the nucleus. The nucleus has protons and neutrons. As protons have positive charge and neutrons have no charge the nucleus has a positive charge.

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The drawings show two examples in which a ray of light is refracted at the interface between two liquids. In each example the in
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Answer:

Possible options:

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B. nA, nB, nC

C. nC, nB, nA

D. nC, nA, nB

E. nB, nA, nC

Answer is D

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When the light is refracted into liquid B it is bent away from the normal, so that nA > nB. When the light is refracted into liquid C it is bent toward the normal, so that nC > nA. Therefore, we conclude that nC > nA > nB

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