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Gnom [1K]
2 years ago
15

Im confused on number one

Physics
1 answer:
mr Goodwill [35]2 years ago
5 0

Explanation:

v=?, u=0, a=?, S=22m.

Using the formula, S=ut+½at²

22={0×5}+(½.a.5²)

22=½.a.5²

a=44/25 = 1.76m/s².

Therefore, net force = work done = ma = 48×1.76 = 84.48N.

therefore, power = work done/time = 84.48/5 = 16.896W.

hope this helps you.

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"The burning of fossil fuels produces gases which are capable of trapping heat resulting into the current rise in the global tem
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a. True

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4 years ago
If a ball that is 10 meters above the ground is thrown horizontally at 5.51 meters per second. a. how long will it take for the
GalinKa [24]

Answer:

a. t = 1.43 s

b. d = 7.88 m

Explanation:

a. The time of flight can be found using the following equation:

y_{f} = y_{0} + v_{0_{y}}t - \frac{1}{2}gt^{2}

Where:

y_{f}: is the final height = -10 m

y_{0}: is the initial height = 0

v_{0_{y}}: is the initial speed in the vertical direction = 0

g: is the acceleration due to gravity = 9.81 m/s²

By solving the above equation for "t" we have:

t = \sqrt{\frac{2y_{f}}{g}} = \sqrt{\frac{2*10 m}{9.81 m/s^{2}}} = 1.43 s

Hence, the ball will hit the ground in 1.43 s.

b. The distance in the horizontal direction can be found as follows:

x_{f} = x_{0} + v_{0}t + \frac{1}{2}at^{2}

Where:

x₀: is the initial position in the horizontal direction = 0

a: is the acceleration in the horizontal direction = 0 (it is moving at constant speed)

x_{f} = 5.51 m/s*1.43 s = 7.88 m

Therefore, the ball will travel 7.88 m before it hits the ground.

I hope it helps you!

4 0
3 years ago
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