Answer: 0.0793
Step-by-step explanation:
Let the IQ of the educated adults be X then;
Assume X follows a normal distribution with mean 118 and standard deviation of 20.
This is a sampling question with sample size, n =200
To find the probability that the sample mean IQ is greater than 120:
P(X > 120) = 1 - P(X < 120)
Standardize the mean IQ using the sampling formula : Z = (X - μ) / σ/sqrt n
Where; X = sample mean IQ; μ =population mean IQ; σ = population standard deviation and n = sample size
Therefore, P(X>120) = 1 - P(Z < (120 - 118)/20/sqrt 200)
= 1 - P(Z< 1.41)
The P(Z<1.41) can then be obtained from the Z tables and the value is 0.9207
Thus; P(X< 120) = 1 - 0.9207
= 0.0793
Answer:
x = 4
Step-by-step explanation:
Given the 2 equations
2x - y = 11 → (1)
x + 3y = - 5 → (2)
Multiply (1) by 3 and add to (2) to eliminate the y- term
6x - 3y = 33 → (3)
Add (2) and (3) term by term to eliminate y, that is
7x = 28 ( divide both sides by 7 )
x = 4
Answer:

Step-by-step explanation:
The given differential equation is 
The characteristics equation is given by

Finding the values of r

We got a repeated roots. Hence, the solution of the differential equation is given by

On differentiating, we get

Apply the initial condition y (0)= 3 in equation (i)

Now, apply the initial condition y' (0)= 13 in equation (ii)

Therefore, the solution of the differential equation is
