Question

find the probability of being delt 5 clubs and 3 cards with one of each remaining suit in 8 card poker

Answer 1

Answer: 0.003757(approx).

Step-by-step explanation:

Total number of combinations of selecting r things out of n things is given by:-

$^nC_r=\dfrac{n!}{r!(n-r)!}$

Total cards in a deck = 52

Total number of ways of choosing 8 cards out of 52 = $^{52}C_8$

Total number of ways to choose 5 clubs and 3 cards with one of each remaining suit = $^{13}C_5\times^{13}C_1\times^{13}C_1\times^{13}C_1$  [since 1 suit has 13 cards]

The required probability = $=\dfrac{^{13}C_5\times^{13}C_1\times^{13}C_1\times^{13}C_1}{^{52}C_8}$

$=\dfrac{\dfrac{13!}{5!8!}\times13\times13\times13}{\dfrac{52!}{8!44!}}\\\\=\dfrac{24167}{6431950}\\\\\approx0.003757$

Hence, the required probability is 0.003757 (approx).