Given:
The expression is

The steps are given.
To find:
The mistake in her steps.
Solution:
We have,

The correct steps are shown below.
Step 1: Taking out x as common factor.

Step 2: Now, taking out 2x² as common factor from first two terms (first group of terms) and -1 form last two terms (second group of terms) in the parentheses.

Step 3: Taking out (x+1) as common factor.

She incorrectly factored -1 from the second group of terms.
Therefore, the correct option is B.
The bearing of the plane is approximately 178.037°. 
<h3>Procedure - Determination of the bearing of the plane</h3><h3 />
Let suppose that <em>bearing</em> angles are in the following <em>standard</em> position, whose vector formula is:
(1)
Where:
- Magnitude of the vector, in miles per hour.
- Direction of the vector, in degrees.
That is, the line of reference is the
semiaxis.
The <em>resulting</em> vector (
), in miles per hour, is the sum of airspeed of the airplane (
), in miles per hour, and the speed of the wind (
), in miles per hour, that is:
(2)
If we know that
,
,
and
, then the resulting vector is:

![\vec v = (7.986, -232.981) \,\left[\frac{mi}{h} \right]](https://tex.z-dn.net/?f=%5Cvec%20v%20%3D%20%287.986%2C%20-232.981%29%20%5C%2C%5Cleft%5B%5Cfrac%7Bmi%7D%7Bh%7D%20%5Cright%5D)
Now we determine the bearing of the plane (
), in degrees, by the following <em>trigonometric</em> expression:
(3)


The bearing of the plane is approximately 178.037°. 
To learn more on bearing, we kindly invite to check this verified question: brainly.com/question/10649078
Answer:
I'm not sure what you want me to answer from this, so I solved for every variable:
Angle A: 83°
Side b: 6.29
Side c: 5.8
Step-by-step explanation:
-----Angle A:
Since the sum of the interior angles of a triangle ALWAYS equal 180°, we can solve for angle A as follows:

-----Side b:
Here, we use the sin rule for finding sides, since we know all of the angles as well as one side:

-----Side c:
