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Len [333]
4 years ago
11

How to model 23 less than 55 on a number line

Mathematics
2 answers:
Zina [86]4 years ago
7 0
55 minus 23take a number line go to 55 and jump back 23 spaces
nydimaria [60]4 years ago
5 0

Answer:

Here the given subtraction problem,

55 - 23

For finding the answer with help of the number line we will follow the following steps,

Step 1 : First find the number 55 on the number line.

Step 2: Count the position of 55 from 0 of the number line,

Step 3: Now count back from 55 to 23,

We will get  32.

Thus, 55 - 23 = 32.

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Column A                                            Column B

1. x² + 6x + 8                                        x-3,x+2

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Step-by-step explanation:

Column A                                            Column B

1. x² + 6x + 8                                        x-3,x+2

2. x³ - 7x + 6                                       x+1, x+2, x+3

3. x³ - 2x² - 5x + 6                              x-1, x+2, x-3

Using Factor theorem we put values of x = ±1,±2,±3 in each of the polynomials unless we get a zero.

1. x² + 6x + 8      

= 1+6(1) +8= 15

1. x² + 6x + 8

  4+ 12+8 = 24

1. x² + 6x + 8

 (-1)² + 6(-1)+ 8

= 1-6+8= 3

1. x² + 6x + 8

 (-2)² + 6(-2)+ 8

= 4-12+8= 0

1. x² + 6x + 8

(3)²+ 6(3) +8

= 9+18+8 ≠ 0

1. x² + 6x + 8

(-3)²+ 6(-3) +8

= 9-18+8 =-1

For this polynomial we have x+2= 0 or x=-2, x-3= 0 , x=3

2. x³ - 7x + 6

1-7+6= 0

2. x³ - 7x + 6

(-1)³-7(-1) +6

= 13-1≠0

2. x³ - 7x + 6

(2)³-7(2) +6

= 8-14+6= 0

2. x³ - 7x + 6

(-2)³-7(-2) +6

= -8 +14+6

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= 0

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= -1 -2 +5+6

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(2)³-2(2)²-5(2)+6

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3. x³ - 2x² - 5x + 6

(-2)³-2(-2)²-5(-2)+6

= -8-8+10+6

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(3)³-2(3)²-5(3)+6

= 27-18-15+6

=0

3. x³ - 2x² - 5x + 6

(-3)³-2(-3)²-5(-3)+6

= -27-18+15+6

=-14

For this polynomial we have x-1= 0 ,x+2=0, x-3= 0or x=1,-2,3

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