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Romashka [77]
3 years ago
6

Pls help me!!!!!!!!!!!!!!!!

Mathematics
1 answer:
dusya [7]3 years ago
5 0
Homeroom 6a is part to part
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Which of the following functions is graphed below?
Paul [167]
The graph shows a piecewise function, meaning that different functions are shows at different intervals (ranges of x-values). 

1) One of the graphs is part of a parabola, meaning the equation is quadratic (has x^{2}). That equation must be x^{2} + 4.
2) The other graph is a straight line, meaning it must be a linear equation. That equation must be x + 4.

Looking at the entire graph, you can see that the parabola starts from the left and ends with an open circle at x=2. An open circle means that the graph doesn't have a value at that point, x=2. The linear line starts with a filled point at x=2 and continues to the right. That means we're looking for the choice where:
1) x^{2} + 4  \ \textless \  2
Since x=2 cannot be a point in the graph, and less than 2 means that the graph includes everything to the left of 2, but not including 2

2) x + 4  \geq  2
Since x=2 is a point in the graph, and greater than or equal to 2 means that the graph includes 2 and everything to the right of it

------

Answer: C) y = \left \{ {{x^{2} + 4  \textless \ 2} \atop {x + 4 \: \geq \: 2}} \right.



6 0
3 years ago
Solve using zero property : (x-7)(x+10) = 0
Alla [95]

Answer:

Step-by-step explanation:

Aight

so

x^2+3x−70=0

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Valentin [98]

Answer:

0.387

Step-by-step explanation:

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3 years ago
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Find a cubic function with the given zeros. -6, 7, -4
Nookie1986 [14]
f(x)=a(x-x_1)(x-x_2)(x-x_3)\\\\x_1=-6;\ x_2=7;\ x_3=-4\\\\f(x)=(x+6)(x-7)(x+4)=(x^2-x-42)(x+4)\\\\=x^3+3x^2-46x-168
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Rus_ich [418]

Answer:

36

Step-by-step explanation:

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