Answer:
72.67g of B
Explanation:
The reaction of B₂O₃ to produce boron (B), is:
B₂O₃ → 3/2O₂ + 2B
<em>That means B₂O₃ produce 2 moles of boron</em>
Molar mass of B₂O₃ is 69.62g/mol. 234g of B₂O₃ contains:
234g B₂O₃ ₓ (1mol / 69.62g) = 3.361 moles of B₂O₃.
As 1 mole of B₂O₃ produce 2 moles of B, Moles of B that can be produced from B₂O₃ is:
3.361mol B₂O₃ ₓ 2 = <em>6.722 moles of B</em>.
As molar mass of B is 10.811g/mol. Thus mass of B that can be produced is:
6.722mol B ₓ (10.811g / mol) = <em>72.67g of B</em>
We say that the solution is unsaturated.
Explanation:
If the salt solubility is 36 g in 0.1 L of water then we can dissolve 360 g of salt in 1 L of water.
Because the solution contains 200 g of salt in 1 L of water, the solution is unsaturated because more salt can be added until we reach the saturation point.
We call the solution dilute when we compare the concentration of a solution with the concentration of another solution, but here we do not compare different solutions.
Learn more about:
solubility
brainly.com/question/9126711
#learnwithBrainly
NaCI this wht forms when sodium and choride combine
N2 + 3H2 -----> 2NH3
3 mol 2 mol
When 3 mol H2 react completely 2 mol NH3 are formed.
Answer:
128g
Explanation:
Simply multiply the number of moles by the molar mass of each substance (64 g/mol for SO2 and 32 g/mol for 02):
SO₂ → 2 moles × 64 g/mol =128g
O₂ → 1 mole x 32 g/mol =32g
