Give an example of a physical property that is also a characteristic property

Wich has more energy rolling down a hill - a bowling ball or soccer ball? Explain your answer

goldfiish [28.3K]

Answer:

Bowling ball

Explanation:

They are traveling at the same speed, but the bowling ball has more mass. The bowling ball has more kinetic energy because more force is needed to stop the rolling bowling ball. Two balls with different masses moving at the same speed have different amounts of kinetic energy.

6 0

2 years ago

Read 2 more answers

Neutral atoms of the same element can differ in their number of

konstantin123 [22]

Answer:

a. neutron

Explanation:

A neutral atom has the same number of protons and electrons because in order for it to be a neutral atom the charges must be the same.

a neutron has no charge therefore it can be different then the number of protons and electrons in a neutral atom as it won't affect the charge.

7 0

2 years ago

For the reaction A+B+C→D+E, the initial reaction rate was measured for various initial concentrations of reactants. The followin

Studentka2010 [4]

Answer : The initial rate for a reaction will be $3.63\times 10^{-4}Ms^{-1}$

Explanation :

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

$A+B+C\rightarrow D+E$

Rate law expression for the reaction:

$\text{Rate}=k[A]^a[B]^b[C]^c$

where,

a = order with respect to A

b = order with respect to B

c = order with respect to C

Expression for rate law for first observation:

$1.2\times 10^{-4}=k(0.40)^a(0.40)^b(0.40)^c$ ....(1)

Expression for rate law for second observation:

$3.6\times 10^{-4}=k(0.40)^a(0.40)^b(1.20)^c$ ....(2)

Expression for rate law for third observation:

$4.8\times 10^{-4}=k(0.80)^a(0.40)^b(0.40)^c$ ....(3)

Expression for rate law for fourth observation:

$4.8\times 10^{-4}=k(0.80)^a(0.80)^b(0.40)^c$ ....(4)

Dividing 1 from 2, we get:

$\frac{3.6\times 10^{-4}}{1.2\times 10^{-4}}=\frac{k(0.40)^a(0.40)^b(1.20)^c}{k(0.40)^a(0.40)^b(0.40)^c}\\\\3=3^c\\c=1$

Dividing 1 from 3, we get:

$\frac{4.8\times 10^{-4}}{1.2\times 10^{-4}}=\frac{k(0.80)^a(0.40)^b(0.40)^c}{k(0.40)^a(0.40)^b(0.40)^c}\\\\4=2^a\\a=2$

Dividing 3 from 4, we get:

$\frac{4.8\times 10^{-4}}{4.8\times 10^{-4}}=\frac{k(0.80)^a(0.40)^b(0.40)^c}{k(0.80)^a(0.80)^b(0.40)^c}\\\\1=2^b\\b=0$

Thus, the rate law becomes:

$\text{Rate}=k[A]^2[B]^0[C]^1$

Now, calculating the value of 'k' by using any expression.

Putting values in equation 1, we get:

$1.2\times 10^{-4}=k(0.40)^2(0.40)^0(0.40)^1$

$k=1.875\times 10^{-3}M^{-2}s^{-1}$

Now we have to calculate the initial rate for a reaction that starts with 0.55 M of reagent A and 0.80 M of reagents B and C.

$\text{Rate}=k[A]^2[B]^0[C]^1$

$\text{Rate}=(1.875\times 10^{-3})\times (0.55)^2(0.80)^0(0.80)^1$

$\text{Rate}=3.63\times 10^{-4}Ms^{-1}$

Therefore, the initial rate for a reaction will be $3.63\times 10^{-4}Ms^{-1}$

4 0

3 years ago

Hydrogen selenide (H2Se) reacts with water according to the following equation.

LekaFEV [45]

H2Se is the acid as it is donating H+ to H2O and forming SeH- (which is conjugate base).

H2O is the base since it’s receiving H+ from H2Se to form H3O+ (which is the conjugate acid)

Se is in the same group as O but is in different period which means Se has higher radius compred to O. this led to H-O bond being stronger than H-Se bond and H-Se bond which in turn makes it easier for H2Se to donate H to H2O

4 0

2 years ago

At what velocity (m/s) must a 20.0g object be moving in order to possess a kinetic energy of 1.00J

user100 [1]

Answer:

10 ms-1

Explanation:

Kinetic energy = 1/2 × m × v^2

1 = 1/2× 20 ×10^ -3 × v^2

v ^ 2 = 100

v = 10 ms-1

note : convert grams in to kg before substitution as above

7 0

3 years ago