Ionic bonds happen when Metals give electron to non-metals and covalent bonds happen when Non-metals give electrons away. Knowing this:
-NaF = ionic (Na is a metal, F is a non-metal)
-NF3 = Covalent (N is a non-metal, F is a non-metal)
-SiF4 = Ionic (Si is a metalloid, F is non-metal)
-CaF2 = ionic (Ca is a metal, F is a non-metal)
-NH4F = covalent (N is a non-metal, H is a non-metal, F is a non-metal)
Hope this helps
Answer:
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Explanation:
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The pounds of alum produced when 0.26 g of hydrogen was produced are 0.0434 lb.
First, let's convert 0.126 g of hydrogen to moles using its molar mass (2.02 g/mol).
![0.126 g \times \frac{1moo}{2.02 g} = 0.0624 mol](https://tex.z-dn.net/?f=0.126%20g%20%5Ctimes%20%5Cfrac%7B1moo%7D%7B2.02%20g%7D%20%3D%200.0624%20mol)
Let's consider the steps to make alum (KAl(SO₄)₂⋅12H₂O) from aluminum (Al).
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2 Al(s) + 2 KOH(aq) + 6 H₂O(l) →2 KAl(OH)₄(aq) + 3 H₂(g)
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2 KAl(OH)₄(aq) + H₂SO₄(aq) → 2 Al(OH)₃(s) + K₂SO₄(aq) + 2 H₂O(l)
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2 Al(OH)₃(s) + H₂SO₄(aq) → Al₂(SO₄)₃(aq) + 6 H₂O(l)
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K₂SO₄(aq) + Al₂(SO₄)₃(aq) + 24 H₂O(l) → 2 KAl(SO₄)₂⋅12H₂O(s)
To relate H₂ to KAl(SO₄)₂⋅12H₂O, we need to consider the appropriate molar ratios:
- In step 1, the molar ratio of H₂ to KAl(OH)₄ is 3:2.
- In step 2, the molar ratio of KAl(OH)₄ to Al(OH)₃ is 2:2.
- In step 3, the molar ratio of Al(OH)₃ to Al₂(SO₄)₃ is 2:1.
- In step 4, the molar ratio of Al₂(SO₄)₃ to KAl(SO₄)₂⋅12H₂O is 1:2.
The moles of KAl(SO₄)₂⋅12H₂O produced from 0.0624 moles of H₂ are:
![0.0624 molH_2 \times \frac{2molKAl(OH)_4}{3molH_2} \times \frac{2molAl(OH)_3}{2molKAl(OH)_4} \times \frac{1molAl_2(SO_4)_3} {2molAl(OH)_3} \times \frac{2molAlum}{1molAl_2(SO_4)_3} =0.0416 mol Alum](https://tex.z-dn.net/?f=0.0624%20molH_2%20%5Ctimes%20%5Cfrac%7B2molKAl%28OH%29_4%7D%7B3molH_2%7D%20%5Ctimes%20%5Cfrac%7B2molAl%28OH%29_3%7D%7B2molKAl%28OH%29_4%7D%20%5Ctimes%20%5Cfrac%7B1molAl_2%28SO_4%29_3%7D%20%7B2molAl%28OH%29_3%7D%20%5Ctimes%20%5Cfrac%7B2molAlum%7D%7B1molAl_2%28SO_4%29_3%7D%20%3D0.0416%20mol%20Alum)
The molar mass of alum is 474.38 g/mol. The mass corresponding to 0.0416 moles is:
![0.0416 mol \times \frac{474.38g}{mol} = 19.7 g](https://tex.z-dn.net/?f=0.0416%20mol%20%5Ctimes%20%5Cfrac%7B474.38g%7D%7Bmol%7D%20%3D%2019.7%20g)
Finally, we convert 19.7 grams to pounds using the conversion factor 1 lb = 454 g.
![19.7 g \times \frac{1lb}{454g} = 0.0434 lb](https://tex.z-dn.net/?f=19.7%20g%20%5Ctimes%20%5Cfrac%7B1lb%7D%7B454g%7D%20%3D%200.0434%20lb)
The pounds of alum produced when 0.26 g of hydrogen was produced are 0.0434 lb.
You can learn more about molar ratios here: brainly.com/question/15973092
The answer to this question is 6.25ml
To answer this question, you need to calculate the azithromycin drug doses for this patient. The calculation would be: 25kg * 10mg/kg/d= 250mg/d
Then multiply the doses with the available drug. It would be:
250 mg/d / (200mg/5ml)= 6.25ml/d
Answer:
sp3d
Explanation:
The ground state electronic configuration of tin is; [Kr] 5s²4d¹⁰5p². Hybridization is a valence bond concept that postulates that orbitals of appropriate energy could be mixed in order to produce suitable orbitals that could be used for bonding.
In the formation of Snf5^ -1, there is a hybridization of the 5p, 5d and 6s orbitals to yield the sp3d orbitals required for the formation of the chemical specie hence the answer.