All categories

4 years ago

Difference between uninsurable and insurable risks

2 answers:

6 0

Uninsurable risk : The risk cannot be estimated and not probable to forsee

Example : You cannot insure you losing or winning the lottery

Insurable Risk : If the risk is can be estimated and probable to forsee

Example : A football player insure their legs from potential injury

hope this helps

Pavel [41]4 years ago

6 0

Difference between uninsurable and insurable risks

Answer: The difference is the following: a risk is uninsurable when the insurance company cannot calculate the probability of the risk. On the other hand a risk is insurable if the insurance company has enough statistics to work out the probability of the risk.

I hope it helps, Regards.

You might be interested in

Define the term production

lidiya [134]

Answer:

$\huge\boxed{Answer\hookleftarrow}$

<h2>Production :-</h2>

✐ Production refers to the process of manufacturing goods from raw materials, or in simpler words, production is the making of something for sale.

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

# ꧁❣ RainbowSalt2²2² ࿐

5 0

3 years ago

A stock just paid an annual dividend of $2.8. The dividend is expected to grow by 6% per year for the next 4 years. The growth r

makvit [3.9K]

Answer:

dsvklnwvnlkwdv

Explanation

mnewnflkkwe

7 0

3 years ago

Madison Corporation's production cycle starts in the Processing Department. The following information is available for April: Un

charle [14.2K]

Answer:

Equivalent Units of Production :

(1) Materials = 298000

(2) Conversion Costs = 284400

(3) Total = 582400

Explanation:

The Concept of Equivalent Units entails identifying number of completed units in terms of their completion % in the input component or process.

Step 1 : Determine Units Completed and Transferred to Finished Goods

Units in Process = Units Output

Units In Process 298000

Less Closing Work In Process 34000

Completed and Transferred 264000 (Balancing figure)

Step 1 : Determine Equivalent Units for each input component

Materials:

Completed and Transferred 100% = 264000×100%= 264000

Closing Work In process 100% = 34000×100%= 34000

Total = 298000

Conversion Costs:

Completed and Transferred 100% = 264000×100%=264000

Closing Work In process 60%=34000×60%=20400

Total =284400

5 0

3 years ago

A marketing manager had a goal to improve market share for his paper plates by 2 percent in the coming year, and he felt he’d ne

rodikova [14]

Answer:

OBJECTIVE AND TASK BUDGETING.

Explanation:

Objective and task budgeting is an effective budgeting strategy which considers the firm’s overall promotional objectives. The budgeting is then done according to the requirements for meeting these goals.

By running television ads and a social media campaign, the marketing manager has created a means to meet his objective or goal which is to improve market share for his paper plates by 2 percent in the coming year. He then proceeds to price how much the advertising would cost him and then sets the budget. This budgeting is done by OBJECTIVE AND TASK BUDGETING. This allows the marketing manager to allocate a certain amount of money to its marketing budget based on his objectives, rather than choosing an arbitrary amount.

3 0

3 years ago

Box office revenue at a multiplex cinema in paris is r(p) = 3600p − 6p3 euros per showing when the ticket price is p euros.

exis [7]

Part A:

Given that Box office revenue at a multiplex cinema in paris is $r(p) = 3600p - 6p^3$ euros per showing when the ticket price is p euros.

When p = 9,

$r(9) = 3600(9) - 6(9)^3 \\ \\ =32,400-6(729)=32,400-4,374 \\ \\ =\bold{28,026 \ euros}$

Part B:

The linear approximation of the change in a function Δf(x) using a value, a, close to x is given by:

$L(a+Δx)=(Δx)f'(a)$

Given that $r(p) = 3600p - 6p^3$ , then $r'(p) = 3600 - 12p^2$

Using a = 9, we have:

$r'(9)=3600-12(9)^2 \\ \\ =3600-12(81)=3600-972 \\ \\ =2,628$

Thus, If p is raised by 0.5 euros, then

$\Delta R=(\Delta p)f'(9) \\ \\ =0.5(2,628)=\bold{1,314 \ euros}$

Part C:

The linear approximation of the change in a function Δf(x) using a value, a, close to x is given by:

$L(a+Δx)=(Δx)f'(a)$

Given that $r(p) = 3600p - 6p^3$ , then $r'(p) = 3600 - 12p^2$

Using a = 9, we have:

$r'(9)=3600-12(9)^2 \\ \\ =3600-12(81)=3600-972 \\ \\ =2,628$

Thus, If p is lowered by 0.5 euros, then

$\Delta R=(\Delta p)f'(9) \\ \\ =-0.5(2,628)=\bold{-1,314 \ euros}$

4 0

4 years ago