What are two things that can be done to maximize the chances of recovering parasites from a fecal smear?

1 answer:

7 0

Sedimentation - uses solutions of lower specific gravity than the organisms, which concentrated in the sediment. This technique is recommended for general diagnostic laboratories because it is easy to perform and less prone to technical errors.

Flotation - this technique uses solutions of higher specific gravity than the parasitic organisms so the organisms float and the debris sinks producing a cleaner material while the disadvantage is that walls of cysts and eggs collapse that may blocking its identification.

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Curiosity after a step is completed, when your new hypothesis is more probable than your prior one

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N pea plants, yellow (Y) seed color is a dominant trait, and green seed color (y) is a recessive trait. Which resulting plant wi

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I believe the answer is Yy. Although Y represents the dominant trait for yellow, it being paired with the recessive trait, y, has the chance of a plant with green seeds to be produced in the next generation.

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A controlled experiment___. A. Includes one group for which the scientist controls all variables. B. Includes at least two group

notsponge [240]

Answer:

The correct answer is:

Includes at least two groups, one of which does not receive the experimental treatment. (B)

Explanation:

A controlled experiment is made up of at least two groups of participants (subjects). One group (the test group) receives the experimental treatment, which can be an intervention or a new drug to be tested etc, and the effect of the treatment on the subjects is measured, while the second group of similar subjects also known as the control group acts as a baseline and do not receive the treatment or intervention. They act as a baseline to ensure that the change observed in the treatment group was brought about as a result of the treatment.

Note that repeating the experiment several times does not ensure accuracy of the result, rather it ensures reliability of the results hence option D is not correct

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2 years ago

Describe how the output of the Krebs cycle can be modified in additional processes of the carbon cycle.

Murljashka [212]

Answer:

Step 1. A carboxyl group is removed from pyruvate, releasing a molecule of carbon dioxide into the surrounding medium. (Note: carbon dioxide is one carbon attached to two oxygen atoms and is one of the major end products of cellular respiration. ) The result of this step is a two-carbon hydroxyethyl group bound to the enzyme pyruvate dehydrogenase; the lost carbon dioxide is the first of the six carbons from the original glucose molecule to be removed. This step proceeds twice for every molecule of glucose metabolized (remember: there are two pyruvate molecules produced at the end of glycolysis); thus, two of the six carbons will have been removed at the end of both of these steps.

Step 2. The hydroxyethyl group is oxidized to an acetyl group, and the electrons are picked up by NAD+, forming NADH (the reduced form of NAD+). The high- energy electrons from NADH will be used later by the cell to generate ATP for energy.

Step 3. The enzyme-bound acetyl group is transferred to CoA, producing a molecule of acetyl CoA. This molecule of acetyl CoA is then further converted to be used in the next pathway of metabolism, the citric acid cycle.

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