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3 years ago

15

What is the algebraic expression for "the difference between seven times a number and three times that number"? 7 - 3 x 7 x - 3

7 x - 3 x

2 answers:

DedPeter [7]3 years ago

8 0

7x-3x is prob the answer

Vika [28.1K]3 years ago

3 0

The answer would be 7n - 3n. Please mark brainliest. Btw if it's a multi-choice question, post the answers one at a time below.

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Can Somebody Please Explain How To Do It? THANKS

sergejj [24]

Hello from MrBillDoesMath!

Answer:

9

Discussion:

Solution 1:

Distance between two points (x1, y1), (x2,y2) is given by the formula

sqrt( (x1-x2)^2 + (y1-y2)^2). In our case this becomes

sqrt( (0-0)^2 + (12 -3)^2 ) =

sqrt( 9^2) =

9.

Solution 2:

Note points D and E both have x = 0 so segment DE is a vertical segment. The length is simply the difference of the y coordinates: 12- 3 = 9 as before.

Thank you,

MrB

6 0

3 years ago

Converse of the Pythagorean theorem

jonny [76]

I only know how to do # 7.

7. 4.5^2 + 6^2 = 7.5^2
20.25 + 36 = 56.25
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7 0

3 years ago

Solve the inequality for x<br> 3^(6x+18)<27^(3x)

Lera25 [3.4K]

Answer:

$\displaystyle x > 6$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

<u>Algebra I</u>

Terms/Coefficients
Factoring

<u>Algebra II</u>

Exponential Rule [Powering]: $\displaystyle (b^m)^n = b^{m \cdot n}$
Solving exponential equations

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

<em /> $\displaystyle 3^{6x + 18} < 27^{3x}$ <em />

<em />

<u>Step 2: Solve for </u><em><u>x</u></em>

Rewrite: $\displaystyle 3^{6x + 18} < 3^{3(3x)}$
Set: $\displaystyle 6x + 18 < 3(3x)$
Factor: $\displaystyle 3(2x + 6) < 3(3x)$
[Division Property of Equality] Divide 3 on both sides: $\displaystyle 2x + 6 < 3x$
[Subtraction Property of Equality] Subtract 3x on both sides: $\displaystyle -x + 6 < 0$
[Subtraction Property of Equality] Subtract 6 on both sides: $\displaystyle -x < -6$
[Division Property of Equality] Divide -1 on both sides: $\displaystyle x > 6$

8 0

3 years ago

Read 2 more answers

Reduce the following lambda-calculus term to the normal form. Show all intermediate steps, with one beta reduction at a time. In

QveST [7]

Answer:

Step-by-step explanation:

Reduction to normal from using lambda-reduction:

The given lambda - calculus terms is, (λf. λx. f (f x)) (λy. Y * 3) 2

For the term, (λy. Y * 3) 2, we can substitute the value to the function.

Therefore, applying beta- reduction on "(λy. Y * 3) 2" will return 2*3= 6

So the term becomes,(λf. λx. f (f x)) 6

The first term, (λf. λx. f (f x)) takes a function and an argument, and substitute the argument in the function.

Here it is given that it is possible to substitute the resulting multiplication in the result.

Therefore by applying next level beta - reduction, the term becomes f(f(f(6)) (f x)) which is in normal form.

4 0

3 years ago

Solve for x in the triangle.Round your answer to the nearest tenth.

enyata [817]

sin = opposite/hypotenuse

sin 40° = 12/x

Cross multiply.

0.64278760968x = 12

Divide both sides by sin 40°.

x = 18.7 (rounded to nearest tenth).

5 0

3 years ago

Read 2 more answers