All categories

3 years ago

Write the polynomial in standard form and identify the zeros of the function and the x-intercepts of its graph.

1 answer:

3 0

$f(x)=(x-3i)(x+3i)
\\f(x)=x^2-(3i)^2
\\f(x)=x^2-9i^2
\\f(x)=x^2-9(-1)
\\f(x)=x^2+9$

x-intercepts of its graph

 $f(x)=0
\\(x-3i)(x+3i)=0
\\x-3i=0 \Rightarrow x=3i
\\x+3i=0 \Rightarrow x=-3i$

You might be interested in

Simplify the expression –3(x 3)2 – 3 3x. what is the simplified expression in standard form?

777dan777 [17]

$-3(x^{2} +5x+10)$ is the standard form of the given expression

The given expression is:

$=-3(x+3)^{2} -3+3x\\\\=-3*(x^{2} +2*3*x+3^{2} )-3+3x\\\\=-3x^{2} -3*6x-3*9-3+3x\\\\=-3x^{2} -18x-27-3+3x\\\\=-3x^{2} -15x-30\\\\=-3(x^{2} +5x+10)$

This is the standard form of the given expression.

Learn more about Simplifying expression here brainly.com/question/723406

#SPJ4

7 0

2 years ago

What is the value of x in the diagram? A. 100 B. 120 C. 60 D. 50

Delicious77 [7]

The answer is b 120 . you add the angles

4 0

4 years ago

Read 2 more answers

The sum of the first 10 terms of an arithmetic sequence is 235 and the

Degger [83]

Answer:

$\bold{a_1 = -42.65}\\\\\bold{d=14.7}$

Step-by-step explanation:

The sum of the first 10 terms of an arithmetic sequence is:

$S_{10}=a_1+a_2+...+a_{10}=\dfrac{a_1+a_{10}}{2}\cdot10=\dfrac{2a_1+(10-1)d}{2}\cdot10$

$\dfrac{2a_1+(10-1)d}{2}\cdot10=235\\\\(2a_1+9d)\cdot5=235\\\\2a_2+9d=47$

the sum of the second 10 terms is: a₁₁ + a₁₂+...+ a₂₀

And the sum of the first 20 terms of an arithmetic sequence is:

$S_{20}=a_1+a_2+...+a_{10}+a_{11}+...+a_{20}=\dfrac{2a_1+(20-1)d}{2}\cdot10$

so the sum of the second 10 terms is:

$a_{11}+a_{12}+...+a_{20}=S_{20}-S_{10}$

Therefore we have:

$\dfrac{2a_1+(20-1)d}{2}\cdot10-\dfrac{2a_1+(10-1)d}{2}\cdot10=735\\\\(2a_1+19d)\cdot5-(2a_1+9d)\cdot5=735\\\\2a_1+19d-(2a_1+9d)=147\\\\10d=147\\\\d=14.7$

and:

$2a_1+9\cdot14.7=47\\\\2a_1+132.3=47\\\\2a_1=-85.3\\\\a_1=-42,65$

3 0

3 years ago

Evaluate x square2 +12,when x=3

GarryVolchara [31]

Answer:

Step-by-step explanation:

3^2=9

9+12=21

Keep it up

6 0

3 years ago

Jose is training for a marathon.If he ran 160.2 miles in january, 163.2 miles in February, 157.8 miles in march, and 159 miles i

SVETLANKA909090 [29]

Answer: I think it's 960.

Step-by-step explanation:

Add up all of the numbers:

(160.2+163.2+157.8+159) = 640.2

Find the average by diving 640.2 by how many numbers there are:

640.2 ÷ 4 = 160.05

Round that average^^:

160.05 >>> 160

Multiply by how many numbers there will be:

In this case, your job is to estimate how far Jose ran in 6 months, not just those 4. So instead of multiplying the average (160) by 4, you'd multiply it by 6.

160 x 6= 960

3 0

3 years ago