The probability of event A and B to both occur is denoted as P(A ∩ B) = P(A) P(B|A). It is the probability that Event A occurs times the probability that Event B occurs, given that Event A has occurred.
So, to find the probability that you will be assigned a poem by Shakespeare and by Tennyson, let Event A = the event that a Shakespeare poem will be assigned to you; and let Event B = the event that the second poem that will be assigned to you will be by Tennyson.
At first, there are a total of 13 poems that would be randomly assigned in your class. There are 4 poems by Shakespeare, thus P(A) is 4/13.
After the first selection, there would be 13 poems left. Therefore, P(B|A) = 2/12
Based on the rule of multiplication,
P(A ∩ B) = P(A) P(B|A)P(A ∩ B) = 4/13 * 2/12
P(A ∩ B) = 8/156
P(A ∩ B) = 2/39
The probability that you will be assigned a poem by Shakespeare, then a poem by Tennyson is 2/39 or 5.13%.
Answer:
f(-3) = -76
g(7) = 38
Step-by-step explanation:
Answer:
4+√55= 11.42
4-√55= -3.42
Step-by-step explanation:
- w² − 8w − 39 = 0
- w²- 2*4w + 16- 55=0
- (w-4)²=55
- w-4=√55 ⇒ w= 4+√55= 11.42
- w-4=- √55 ⇒ w= 4-√55= -3.42
Answer:
A
Step-by-step explanation:
two real solutions! hope this helped!!
