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son4ous [18]
3 years ago
12

Two fourth is _____________ pieces of the whole

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
7 0
1/2 pieces of the hole because you can simplify 2/4 by dividing it by 2 and you'll get 1/2
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Please help! I’m a little behind in math rn and could use help on this :))- Graph above!!!
weeeeeb [17]
C because you need to do a2+b2=c2
5 0
3 years ago
Read 2 more answers
What is the x intercept ?
o-na [289]

Answer:

(3,0)

Step-by-step explanation:

The x-intercept of the line is where the line crosses the x-axis and the y-value is 0.

This line has a slope of

m = \frac{y_2-y_1}{x_2-x_1}= \frac{-48--64}{-15--21} =\frac{-48+64}{-15+21} =\frac{16}{6} =\frac{8}{3}

This means that when -32 becomes -32+8=-24 then its x-value is -9+3 = -6.

Continue this pattern until the y value is 0.

-32+8 = -24 and -9+3 = -6

-24+8 = -16 and -6+3 = -3

-16 + 8 = -8 and -3+3=0

-8+8=0 and 0+3 = 3

The x intercept is (3,0).

5 0
4 years ago
3/16 x 6 in the simplest form
SIZIF [17.4K]

Answer:

9/8

Step-by-step explanation:

3/16 x 6=18/16=9/8

8 0
2 years ago
Read 2 more answers
Show work please and thanks!
kompoz [17]
Do you understand what I did here?

5 0
3 years ago
SOLUTION We observe that f '(x) = -1 / (1 + x2) and find the required series by integrating the power series for -1 / (1 + x2).
Ann [662]

Answer:

Required series is:

\int{\frac{-1}{1+x^{2}} \, dx =-x+\frac{x^{3}}{3}-\frac{x^{5}}{5}+\frac{x^{7}}{7}+.....

Step-by-step explanation:

Given that

                           f'(x) = -\frac{1}{1 + x^{2}} ---(1)

We know that:

                  \frac{d}{dx}(tan^{-1}x)=\frac{1}{1+x^{2}} ---(2)

Comparing (1) and (2)

                           f'(x)=-(tan^{-1}x) ---- (3)

Using power series expansion for tan^{-1}x

f'(x)=-tan^{-1}x=-\int {\frac{1}{1+x^{2}} \, dx

= -\int{ \sum\limits^{ \infty}_{n=0} (-1)^{n}x^{2n}} \, dx

= -\sum{ \int\limits^{ \infty}_{n=0} (-1)^{n}x^{2n}} \, dx

=-[c+\sum\limits^{ \infty}_{n=0} (-1)^{n}\frac{x^{2n+1}}{2n+1}]

=C+\sum\limits^{ \infty}_{n=0} (-1)^{n+1}\frac{x^{2n+1}}{2n+1}

=C-x+\frac{x^{3}}{3}-\frac{x^{5}}{5}+\frac{x^{7}}{7}+.....

as

                 tan^{-1}(0)=0 \implies C=0

Hence,

\int{\frac{-1}{1+x^{2}} \, dx =-x+\frac{x^{3}}{3}-\frac{x^{5}}{5}+\frac{x^{7}}{7}+.....

7 0
4 years ago
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