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Mila [183]
3 years ago
6

This right? ppl giving me mixed answersPlEASE HELPPPP​

Mathematics
1 answer:
almond37 [142]3 years ago
4 0

Answer:

Uh yeah Its right...i think

Just make sure if its right

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Each baby dinosaur made 15 paintings and each adult dinasour made 7 paintings. The entire herd made 208 paintings in total, and
Serggg [28]

Answer:

there are 6 baby dinos and 2

Step-by-step explanation:

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2 years ago
What is the form of the Difference of Squares identity ? A. a ^ 2 - b ^ 2 = (a - b)(a - b) B. a ^ 2 + b ^ 2 = (a - b)(a - b); a
lozanna [386]
A^2 - b^2 = (a-b)(a+b)
To test it, expand the right hand side.
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3 years ago
David had a coupon for the grocery store. He graphed on the x-axis what his total bill would be if he didn’t use the coupon and
vladimir2022 [97]

Answer:

68$ Is your answer

Step-by-step explanation:

Hope this helps

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3 years ago
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When a distribution is mound-shaped symmetrical, what is the general relationship among the values of the mean, median, and mode
yuradex [85]

Answer:

The mean, median, and mode are approximately equal.

Step-by-step explanation:

The mean, median, and mode are <em>central tendency measures</em> in a distribution. That is, they are measures that correspond to a value that represents, roughly speaking, "the center" of the data distribution.

In the case of a <em>normal distribution</em>, these measures are located at the same point (i.e., mean = median = mode) and the values for this type of distribution are symmetrically distributed above and below the mean (mean = median = mode).

When a <em>distribution is not symmetrical</em>, we say it is <em>skewed</em>. The skewness is a measure of the <em>asymmetry</em> of the distribution. In this case, <em>the mean, median and mode are not the same</em>, and we have different possibilities as the mentioned in the question: the mean is less than the median and the mode (<em>negative skew</em>), or greater than them (<em>positive skew</em>), or approximately equal than the median but much greater than the mode (a variation of a <em>positive skew</em> case).  

In the case of the normal distribution, the skewness is 0 (zero).

Therefore, in the case of a <em>mound-shaped symmetrical distribution</em>, it resembles the <em>normal distribution</em> and, as a result, it has similar characteristics for the mean, the median, and the mode, that is, <em>they are all approximately equal</em>. So, <em>the </em><em>general</em><em> relationship among the values for these central tendency measures is that they are all approximately equal for mound-shaped symmetrical distributions, </em>considering they have similar characteristics of the <em>normal distribution</em>, which is also a mound-shaped symmetrical distribution (as well as the t-student distribution).

5 0
2 years ago
Consider the diagram below.
charle [14.2K]

Answer:

Is D I think

Step-by-step explanation:

4 0
2 years ago
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