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Lilit [14]
3 years ago
11

Solve each given equation and show your work. Tell whether each question has one solution, an infinite number of solutions, or n

o solutions. Explain your answers. (A) 2x+4(x-1)=2+4x. (B) 25-x=15-(3x+10) (C) 4x=2x+2x+5(x-x)
Mathematics
1 answer:
laiz [17]3 years ago
3 0
2x + 4(x - 1) = 2 + 4x
2x + 4x - 4 = 2 + 4x
6x - 4 = 2 + 4x
6x - 4x = 2 + 4
2x = 6
x = 3........there is 1 solution

25 - x = 15 - (3x + 10)
25 - x = 15 - 3x - 10
25 - x = -3x + 5
3x - x = 5 - 25
2x = - 20
x = -20/2
x = -10.....there is 1 solution

4x = 2x + 2x + 5(x - x)
4x = 4x + 5x - 5x
4x = 4x......this has infinite solutions

learn this...
if ur equation ends in a variable equaling a number, then there is one solution.
if ur equation ends in something not equal, like 2 = 4, or 4 = 6, then there is 0 solutions.
if ur equation ends in something equal to something,(the same) like 2 = 2, or 4x = 4x, then there is infinite solutions

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Ksivusya [100]

Answer:

a)

A to B  5 routes and B to C  4 routes

<u>Total options:</u>

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b)

A to C, 20 ways as above calculation.

C to A, 20 ways as well.

<u>Total options:</u>

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c)

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<u>Total options:</u>

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3 years ago
The sum of three consecutive integers is -75.
rusak2 [61]

Answer:

Suppose 3 consecutive integers are X-1,X,X+1

Step-by-step explanation:

Sum = X-1+X+X+1= -78

            3X=-78

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             X= -26

3 consecutive integers are, -27, -26,-25.

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3 years ago
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Deffense [45]

Answer:

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Step-by-step explanation:

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If the polynomial is not factorized we will either factorize to find the zero or use trial and error method.

Since the f(x) in the question is in the factorized form. we will have to equate each factor to zero.

f(x) = (x+3)(x-2)(x-6)

x + 3 = 0 => x = -3

x - 2 = 0 =>  x = 2

x - 6 = 0 => x = 6

8 0
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Answer:

They are on opposite sides of the river ( the riddle never said that they were on the same side )

One simply uses the boat to cross the river and the other person gets into the boat and takes it back to where it started.

Step-by-step explanation:

3 0
3 years ago
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