(a^3/b^7)^2
Bring the power of 2 into the numerator and denominator.
a^6/b^14
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Answer:
https://web2.0calc.com/questions/math-problems_7
#1
m∠A=180 - 115 - 24 = 41°
By the law of sines:
b/sinB = a/sinA ⇒
b = (a*sinB)/sinA = (21*sin24°)/sin41° = (21*0.4067)/0.656 ≈ 13
c/sinC = a/sinA ⇒
c = (a*sinC)/sinA = (21*sin115°)/sin41° = (21*0.9063)/0.656 ≈ 29
#2
m∠C=180 - 119 - 27 = 34°
By the law of sines:
b/sinB = a/sinA ⇒
b = (a*sinB)/sinA = (13*sin119°)/sin27° = (13*0.8746)/0.454 ≈ 25
c/sinC = a/sinA ⇒
c = (a*sinC)/sinA = (13*sin34°)/sin27° = (13*0.5592)/0.454 ≈ 16
#3
m∠C=180 - 57 - 37 = 86°
By the law of sines:
c/sinC = a/sinA ⇒
c = (a*sinC)/sinA = (11*sin86°)/sin57° = (11*0.9976)/0.8387 ≈ 13.1
Angle O=64
Side m=7.3159882(rounded if needed)
Side n=16.68902(round if needed)
We are given
Angle M which equal 26.
Angle N equals 90 degrees
Side MN which equal 15.
We are asked to find all the missing elements of the triangle.
- Angle O can be found using triangle interior theorem so we can add 90+26+x =180 to find the value that satisfies the x value.
Angle O=64 degrees
We can find side m by doing law of sines.
which is 7.315(round if neeeded).
We can find side n using pythagorean theorem,
Side n=16.689(round if needed)
