Answer:
The pH of the solution will be 3
Explanation:
The strength of acids is determined by their ability to dissociate into ions in aqueous solution. A strong acid is any compound capable of completely and irreversibly releasing protons or hydrogen ions, H⁺. That is, an acid is said to be strong if it is fully dissociated into hydrogen ions and anions in solution.
Being pH=- log [H⁺] or pH= - log [H₃O⁺] and being a strong acid, all the HClO₃ dissociates:
HClO₄ + H₂O → H₃O⁺ + ClO₄-
So: [HCLO₄]= [H₃O⁺]
The molar concentration is:

The molar mass of HClO₄ being 100 g / mole, then if 100 grams of the compound are present in 1 mole, 0.025 grams in how many moles are present?

moles of HClO₄= 0.00025
Then:
![[HClO_{4}]=\frac{0.00025 moles}{0.25 L}](https://tex.z-dn.net/?f=%5BHClO_%7B4%7D%5D%3D%5Cfrac%7B0.00025%20moles%7D%7B0.25%20L%7D)
![[HClO_{4}]=0.001 \frac{ moles}{ L}](https://tex.z-dn.net/?f=%5BHClO_%7B4%7D%5D%3D0.001%20%5Cfrac%7B%20moles%7D%7B%20L%7D)
Being [HCLO₄]= [H₃O⁺]:
pH= - log 0.001
pH= 3
<u><em>The pH of the solution will be 3</em></u>
<u><em></em></u>
A 2.200-g sample of quinone (C6H4O2) is burned in a bomb calorimeter whose total heat capacity is 7.854<span> kJ/°C. The temperature of the calorimeter increases from 23.44 to </span>30.57 °C<span>. </span>
Answer:
2AlF₃ + 3Li₂O —> Al₂O₃ + 6LiF
Explanation:
AlF₃ + Li₂O —> Al₂O₃ + LiF
The above equation can be balanced as follow:
AlF₃ + Li₂O —> Al₂O₃ + LiF
There are 2 atoms of Al on the right side and 1 atom on the left side. It can be balance by writing 2 before AlF₃ as shown below:
2AlF₃ + Li₂O —> Al₂O₃ + LiF
There are 6 atoms of F on the left side and 1 atom on the right side. It can be balance by writing 6 before LiF as shown below:
2AlF₃ + Li₂O —> Al₂O₃ + 6LiF
There are 2 atoms of Li on the left side and 6 atoms on the right side. It can be balance by writing 3 before Li₂O as shown below:
2AlF₃ + 3Li₂O —> Al₂O₃ + 6LiF
Thus, the equation is balanced..!