Let the required equation be y = mx + c; where y = 1, m = f'(0), x = 0
f(a) = sec(a)
f'(a) = sec(a)tan(a)
f'(0) = sec(0)tan(0) = 0
y = mx + c
1 = 0(0) + c
c = 1
Therefore, required equation is
y = 1.
Answer:
Greatest is the multiplication exponent by algebra times by the quotient
Step-by-step explanation:
1. Consider the transformation that maps the graph of the function
into the graph of the function
This transmormation has a rule:
(x,y)→(x+2,y)
that is translation 2 units to the right.
2. Consider the transformation that maps the graph of the function
into the graph of the function
This transformation has a rule:
(x,y)→(x,y+3)
that is translation 3 units up.
Answer: correct choice is C.
Answer:
(x, y) = (18, 5)
Step-by-step explanation:
Assuming the three lines meet at a single point at lower left (the figure is sloppily drawn), the angle (3x)°+49° is a corresponding angle to (7x-23)°. That means they have the same measure:
3x +49 = 7x -23
72 = 4x . . . . . . . . . add 23-3x
18 = x . . . . . . . . . . . divide by 4
__
Angles (3x)° and (11y-1)° are "corresponding" angles, so are congruent.
3x = 11y -1
3(18) +1 = 11y . . . . add 1, fill in the value of x
55/11 = y = 5 . . . . divide by 11
The values of x and y are 18 and 5, respectively.
I’m not to sure I was wondering the same thing