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krok68 [10]
3 years ago
6

A chemical that causes a sudden, almost instantaneous release of pressure, gas and heat when subjected to sudden shock, pressure

or high temperatures best describes which type of dot hazardous materials classification?
Chemistry
1 answer:
trasher [3.6K]3 years ago
8 0
The answer to your question is liquid
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1. Which liquid sample is a pure substance?
IRISSAK [1]

The whole Activity , poem and paragraph is missing in the question.

Answer:

(1) Liquid A

(2) Solid A

Explanation:

Using this part of the given poem

Substances and mixtures behave differently,

During boiling and melting most especially

Boiling point of substance is fixed while mixture is not

Substance melts completely but mixture does not

The boiling point of the Pure substance remain fixed after reaching its boiling point this is shown by Liquid A

Solid A is melting completely so Solid A is a pure substance.

6 0
3 years ago
Analyze the food web. If the frog population decreases, what impact will this likely have on the food web?
sergiy2304 [10]

Answer:

the population of grasshoppers will decrease

Explanation:

a food source is becoming more and more limited thus, its predator will also start to die out due to starvation

8 0
3 years ago
Read 2 more answers
What needs more gas a heavealy loaded truck or an empty truck
Vitek1552 [10]
A heavily loaded truck takes more gas because it takes more power to move a heavy load. 
4 0
4 years ago
Description of horizon a
topjm [15]
I like that game Forza horizon

5 0
4 years ago
What is the bond order of li2−? express the bond order numerically?
jeka94
Atomic Number of Lithium is 3, so it has 3 electrons in its neutral state. Also, Li₂ will have 6 electrons. But the chemical formula we are given has a negative charge on it (i.e Li₂⁻) so there is an additional electron (RED) present on this compound. So, the total number of electrons are 7. The MOT diagram for this compound is shown below. According to diagram we are having 4 electrons in Bonding Molecular Orbitals (BMO) and 3 electrons in Anti-Bonding Molecular Orbitals (ABMO). Bond Order is calculated as,

              Bond Order  =  (# of e⁻s in BMO - # of e⁻s in ABMO) ÷ 2

              Bond Order  =  (4 - 3) ÷ 2

              Bond Order  =  1 ÷ 2
Or,
              Bond Order  =  1/2
Or,
              Bond Order  =  0.5

4 0
4 years ago
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