Answer:
18.84
Step-by-step explanation:
sorry if i get the wrong answer i literlly learn this but i complety forget it
Answer:
5.1 days
Step-by-step explanation:
Given in the question,
initial amount of substance = 34 grams
k-value = 0.137
To find the half life of this substance we will use following formula
here N(0) is initial amount of substance
t is time in days
Plug values in the formula
1/2 = e^{-0.137t}
Take logarithm on both sides
ln(1/2) = ln( e^{-0.137t})
ln(1/2) = -0.137t
t = ln(1/2) / -0.137
t = 5.059
t ≈ 5.1 days (nearest to tenths)
Answer:
A3tx-A2b=cdx-2c
Step-by-step explanation:
Distribution
B is the answer!
Explanation:
m^2 n^2 fits into both, you can take m^2 n^2 out of it both.
m is a common factor since you can take m out of both but it’s not the greatest common factor.
2n & 2m wouldn’t even be a common factor bc there is no 2n or 2m in neither.
Answer: The answer would be at 11:45.
Step-by-step explanation: First I though, if they stoppedd for lunch at 1:20 and they've been doing yard work for 1 hour and 35 minutes, I would subtract. 1 hour taken away from 1:20 would be 12:20. Then, since it would be hard to subtract 35 minutes from 12:20, 35 minutes - 20 minutes = 15 minutes. 12:20 subtract 20 minutes = 12:00. 12:00 - 15 minutes equal to 11:45. I hope this helps. I know this explanation can be confusing but it's the best I can do at the moment.
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