The third term of the expansion is 6a^2b^2
<h3>How to determine the third term of the
expansion?</h3>
The binomial term is given as
(a - b)^4
The r-th term of the expansion is calculated using
r-th term = C(n, r - 1) * x^(n - r + 1) * y^(r - 1)
So, we have
3rd term = C(4, 3 - 1) * (a)^(4 - 3 + 1) * (-b)^(3-1)
Evaluate the sum and the difference
3rd term = C(4, 2) * (a)^2 * (-b)^2
Evaluate the exponents
3rd term = C(4, 2) * a^2b^2
Evaluate the combination expression
3rd term = 6 * a^2b^2
Evaluate the product
3rd term = 6a^2b^2
Hence, the third term of the expansion is 6a^2b^2
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Answer:
10t+3
Step-by-step explanation:
Answer:
1. no
2. yes
3. yes
4. yes
5. no
Step-by-step explanation:
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Answer:
x = y = 14
z = 70
Step-by-step explanation:
As we can see from the markings, x = y
So we have an isosceles triangle in ABD
the sum of angles in a triangle is 180
52 + x + y = 180
x + y = 180-52
x + y = 28
so since x = y
x = y = 14
To get z, we have that;
52 + z + 14 + 44 = 180
z + 110 = 180
z = 180-110
z = 70
The indefinite integral will be 
<h3 /><h3>what is indefinite integral?</h3>
When we integrate any function without the limits then it will be an indefinite integral.
General Formulas and Concepts:
Integration Rule [Reverse Power Rule]:
Integration Property [Multiplied Constant]:
Integration Property [Addition/Subtraction]:
![\int [f(x)\pmg(x)]dx=\int f(x)dx\pm \intg(x)dx](https://tex.z-dn.net/?f=%5Cint%20%5Bf%28x%29%5Cpmg%28x%29%5Ddx%3D%5Cint%20f%28x%29dx%5Cpm%20%5Cintg%28x%29dx)
[Integral] Rewrite [Integration Property - Addition/Subtraction]:
[Integrals] Rewrite [Integration Property - Multiplied Constant]:
[Integrals] Reverse Power Rule:
Simplify:
So the indefinite integral will be
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