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mrs_skeptik [129]
3 years ago
9

HEJEKEKFLSKSLCBDMLDgbnnbvgfknfnfkskskfjgjdkwkdjdkdkdkdjdks

Mathematics
2 answers:
mario62 [17]3 years ago
3 0

Answer:

um.... 17??????????????????

Sedbober [7]3 years ago
3 0

Answer:

HDHEHFGEWGDYDGYDHWQFSWDWSQWYUWEHWW8WDWD

Step-by-step explanation:BHDHEJKNHRGHRFYRHDHNHNEBFDYHFBVUUUFHECHFHVYGDFRFHRHFFRUFYYRFFRYFYFYRFREYRYFGFWYBGT

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Can someone please help me!!!​
astra-53 [7]

Answer:

H. 260

Step-by-step explanation:

We'll begin this problem by first figuring out how many students will be able to sit at the first fourteen tables.

14 tables * 14 students = total students

196 = total students ( for those fourteen tables)

Now we also know that sixteen students can sit on the rest of the cafeteria tables.

We need to find the number of tables can hold sixteen students.

To do this, we'll lead with a simple equation:

18 tables total - 14 tables = # of remaining tables

4 = # of remaining tables

Now we're going to do the same thing we did with the original tables:

4 tables * 16 students = total students

64 = total students

Finally, we add both of the tables max values together:

64 + 196 = 260

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3 years ago
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Dima020 [189]
10 -3.5 and 10 -8.5 is the answer I think
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What are the factors of 42
Kaylis [27]
42|2 \\ 21|3 \\ 7 \ |7 \\ 1 \\ \\ \\ \boxed{42=2*3*7}
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A=(1/2)bh Solve the formula for h. Please show the steps of how you got the answer!
Flauer [41]
A = 1/2bh...for h
multiply both sides by 2
2A = bh
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