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Dimas [21]
3 years ago
11

Can someone name one location where you might see fractals in everyday life?

Mathematics
2 answers:
spayn [35]3 years ago
7 0
In a Painting :D Hope this helps!
RSB [31]3 years ago
7 0
A museum​ ;-) hope this helps
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I WILL GIVE BRAINLIEST 6TH GRADE MATH
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Answer:

A

Step-by-step explanation: If you count a the answer will be 48

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50 POINTS! The fifth term of an arithmetic sequence is 11 and the tenth term is 41. What is the first term?
Oxana [17]

<em><u>The common difference d is </u></em>

  • (41–11) / (10–5) = 6.

<em><u>The first term is</u></em>

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<em>so , the first term is -13 </em>

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Solve 5g = 20<br><br><br><br> Please and thank u
Greeley [361]

Answer:

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Step-by-step explanation:

5g = 20

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3 0
3 years ago
The average student-loan debt is reported to be $25,235. A student believes that the student-loan debt is higher in her area. Sh
yulyashka [42]

Answer:

Step-by-step explanation:

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

µ = 25235

For the alternative hypothesis,

µ > 25235

This is a right tailed test.

Since the population standard deviation is not given, the distribution is a student's t.

Since n = 100,

Degrees of freedom, df = n - 1 = 100 - 1 = 99

t = (x - µ)/(s/√n)

Where

x = sample mean = 27524

µ = population mean = 25235

s = samples standard deviation = 6000

t = (27524 - 25235)/(6000/√100) = 3.815

We would determine the p value using the t test calculator. It becomes

p = 0.000119

Since alpha, 0.05 > than the p value, 0.000119, then we would reject the null hypothesis. There is sufficient evidence to support the claim that student-loan debt is higher than $25,235 in her area.

6 0
3 years ago
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