Question

An inequality is shown: −np − 4 ≤ 2(c − 3) Which of the following solves for n?

Answer 1

Answer:

$\huge\boxed{n\leq\dfrac{2-2c}{p}\ \text{for}\ p0}$

Step-by-step explanation:

$-np-4\leq2(c-3)\qquad\text{use the distributive property}\\\\-np-4\leq2c-6\qquad\text{add 4 to both sides}\\\\-np\leq2c-2\qquad\text{change the signs}\\\\np\geq2-2c\qquad\text{divide both sides by}\ p\neq0\\\\\text{If}\ p0 ,\ \text{then}\\\boxed{n\geq\dfrac{2-2c}{p}}$