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diamong [38]
2 years ago
14

An inequality is shown: −np − 4 ≤ 2(c − 3) Which of the following solves for n?

Mathematics
1 answer:
sesenic [268]2 years ago
6 0

Answer:

\huge\boxed{n\leq\dfrac{2-2c}{p}\ \text{for}\ p0}

Step-by-step explanation:

-np-4\leq2(c-3)\qquad\text{use the distributive property}\\\\-np-4\leq2c-6\qquad\text{add 4 to both sides}\\\\-np\leq2c-2\qquad\text{change the signs}\\\\np\geq2-2c\qquad\text{divide both sides by}\ p\neq0\\\\\text{If}\ p0 ,\ \text{then}\\\boxed{n\geq\dfrac{2-2c}{p}}

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4 0
2 years ago
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IS<br> 9/10, 0.9, and<br> 90% equivalent?
wariber [46]

Answer:

yes

Step-by-step explanation:

they are all equivalent because they all equal 0.9

9/10 = 90/100 = 0.9

all percentages can be converted to fraction by putting them over a hundred

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7 0
2 years ago
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Type the missing number in this sequence: 1, 2, 4, 8,​
Phoenix [80]

<u>Answer:</u>

16

<u>Explanation:</u>

what comes next is 16

for the function: y=2^x

6 0
2 years ago
A ship travels 62.5 km in 1st hour of sailing. Starting from 2nd hour, the distance travelled per hour is x% of that in the prec
Bas_tet [7]
Speed of the ship in the second hour =  (62.5 * x ) / 100  kph.

In third hour it is  [(62 * x) / 100 ] * x/100]

is 4th hour its is the above * x/100 again  so we can now form the equation

62.5x      x          x
------- *   ----  *  ----    =  32
100      100      100

62,5 x^3 = 32,000,000
x^3 =  512,000
x = 80 <-----  Answer  to (a)

(b)  Ship travels 62.5 in first hour then  this falls by a common ratio of 0.8 each hour so we have a geometric sequence 

Dist travelled in 6 hours  =  a1  1 - r^n
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                                               1 - r

Answer is    230.56 km 




5 0
3 years ago
In order for figure EFGH to be a trapozoid, which of the following must be true?
kicyunya [14]
You must connect all the letters to create the shape of a trapezoid


7 0
3 years ago
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