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Zielflug [23.3K]
3 years ago
10

What is the value of 10x^3 y^2 when x=-2 and y=-3

Mathematics
2 answers:
lora16 [44]3 years ago
8 0
Hope this helps you :)

Sholpan [36]3 years ago
7 0

Answer:

-720

Step-by-step explanation:

We are given the expression:

10x^3y^2

and asked to evaluate when x= -2 and y= -3.

Therefore, we must substitute -2 for x and -3 for y.

10(-2)^3*(-3)^2

Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition, Subtraction.

Evaluate the first exponent.

⇒ (-2)³ = -2 * -2 * -2= 4*-2= -8

10(-8)*(-3)^2

Evaluate the second exponent.

⇒ (-3)²= -3 * -3= 9

10(-8)*9

Multiply 10 and -8.

-80*9

Multiply -80 and 9.

-720

The value of 10x³y² at x= -2 and y= -3 is -720

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Please help, this chapter was on derivatives...
Usimov [2.4K]
<h3>Answer:  ds/dt = 11</h3>

================================================

Work Shown:

Before we can use derivatives, we need to find the value of s when (x,y) = (15,20)

s^2 = x^2+y^2

s^2 = 15^2+20^2

s^2 = 225+400

s^2 = 625

s = sqrt(625)

s = 25

-----------

Now we can apply the derivative to both sides to get the following.  Don't forget to use the chain rule.

s^2 = x^2 + y^2

d/dt[s^2] = d/dt[x^2 + y^2]

d/dt[s^2] = d/dt[x^2] + d/dt[y^2]

2s*ds/dt = 2x*dx/dt + 2y*dy/dt

2(25)*ds/dt = 2(15)*5 + 2(20)*(10)

50*ds/dt = 150 + 400

50*ds/dt = 550

ds/dt = 550/50

ds/dt = 11

-----------

Side note: The information t = 40 is never used. It's just extra info.

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