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vitfil [10]
3 years ago
7

Please help, this chapter was on derivatives...

Mathematics
1 answer:
Usimov [2.4K]3 years ago
8 0
<h3>Answer:  ds/dt = 11</h3>

================================================

Work Shown:

Before we can use derivatives, we need to find the value of s when (x,y) = (15,20)

s^2 = x^2+y^2

s^2 = 15^2+20^2

s^2 = 225+400

s^2 = 625

s = sqrt(625)

s = 25

-----------

Now we can apply the derivative to both sides to get the following.  Don't forget to use the chain rule.

s^2 = x^2 + y^2

d/dt[s^2] = d/dt[x^2 + y^2]

d/dt[s^2] = d/dt[x^2] + d/dt[y^2]

2s*ds/dt = 2x*dx/dt + 2y*dy/dt

2(25)*ds/dt = 2(15)*5 + 2(20)*(10)

50*ds/dt = 150 + 400

50*ds/dt = 550

ds/dt = 550/50

ds/dt = 11

-----------

Side note: The information t = 40 is never used. It's just extra info.

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Given right triangle ABC, with altitude CD intersecting AB at point D. If AD = 5 and DB = 8, find the length of CD, in simplest
galben [10]

First we dra a triangle:

To prove that the triangles are similar we have to do the following:

Considet triangles ABC and ACD, in this case we notice that angles ACB and ADC are equal to 90°, hence they are congruent. Furthermore angles CAD and CAB are also congruent, this means that the remaining angle in both triangles will also be congruent, therefore by the AA postulate for similarity we conclude that:

\Delta ABC\approx\Delta ACD

Now consider triangles ABC and BCD, in this case we notice that angles ACB and BDC are congruent since they are both equal to 90°. Furthermore angles ABC and DBC are also congruent, this means that the remaining angle in both triangles will, once again, be congruent. Hence by the AA postulate we conclude that:

\Delta ABC\approx\Delta BCD

With this we conclude that traingles BCD and ACD are both similar to triangle ABC, and by the transitivity property of similarity we conclude that:

\Delta ACD\approx BCD

Now that we know that both triangles are similar we can use the following proportion:

\frac{h}{x}=\frac{y}{h}

this comes from the fact that the ratios should be the same in similar triangles.

From this equation we can find h:

\begin{gathered} \frac{h}{x}=\frac{y}{h} \\ h^2=xy \\ h=\sqrt[]{xy} \end{gathered}

Plugging the values we have for x and y we have that h (that is the segment CD) has length:

\begin{gathered} h=\sqrt[]{8\cdot5} \\ =\sqrt[]{40} \\ =\sqrt[]{4\cdot10} \\ =2\sqrt[]{10} \end{gathered}

Therefore, the length of segment CD is:

CD=2\sqrt[]{10}

6 0
2 years ago
Solve for the missing sides and show all the work.
erastovalidia [21]

So, first you must find the remaining angle measure. To do this add 25 and 90 then subtract from 180. The remaining angle measure is 65 degrees.

Next, use tangent, cosine, or sine to find the remaining side lengths.

I used sine of 25 which is opposite of hypo. which is sine 25 = y/43.

Multiply both side by 43 and you get y=18.17

Do the same to find x, but use the sine of 65, and you get sine 65 = x/43.

Multiply both sides by 43 and you get x=38.97

Hope this helped!

3 0
3 years ago
What is the equivalent value of 1/3×(−15)
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What is the equivalent value of 1/3×(−15)
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3 years ago
What is the trigonometric ratio for cos N?
bagirrra123 [75]
If we look at our SOHCAHTOA rule:
cos(x) = adj/hyp

The adjacent side of N is 36, and the hypotenuse is 39.

Therefore:
cos(N) = 36 / 39
5 0
4 years ago
A 2018 Pew Research Center survey found that more Americans believe they could give up their televisions than could give up thei
zloy xaker [14]

The probability that a person could not give up cell phone but could give up television can be expressed as the probability of No could give up cell phone and Yes could give up television, P(NnY) = 0.39

<u>From the two way probability table given</u> :

  • Let, probability that a person could not give up cell phone = N

  • Probability that a person could give up television = Y

The intersection of Y and N = P(Y n N)

  • The probability value at the intersection point using the table given ls 0.39

Therefore, the probability of YnN is 0.39

Learn more :brainly.com/question/18153040

3 0
3 years ago
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