Answer:
In order to have ran 33 miles, Bobby would have to attend <em>32 track practices.</em>
Step-by-step explanation:
Solving this problem entails of uncovering the amount of track practices Bobby must attend in order to have ran 33 miles. Start by reading the problem carefully to break down the information provided.
You can see that Bobby has already ran one mile on his own. This is important to remember for later. The problem also states that he expects to run one mile at every track practice.
Setting up an equation will help us solve. Here is how we could set up the equation:
(<em>amount of miles already ran</em> = 1) + (<em>number of track practices</em> = x) = (<em>total miles to run</em> = 33)
1 + x = 33
The equation is now in place. You can solve this, or isolate <em>'x',</em> by using the subtraction property of equality. This means we will subtract one from both sides of the equation, thus isolating the variable.
1 + x = 33
1 - 1 + x = 33 - 1
x = 32
The variable is the only term left on the left side of the equation. This means Bobby must attend track practice <em>32 times</em> in order to have ran 33 miles.
Answer:
a.) The sum of the weights of the two in insects is 0.0031 grams. (0.0031 grams)
b.) The fly is 0.0013 grams heavier than the gnat. (0.0013 grams)
Step-by-step explanation:
2.2 * 10^-3 = 2.2 * 1/1000 which is 2.2/1000.
9 * 10^-4 = 9 * 1/10000 = 9/10000
To add 9/10000 to 2.2/1000 we have to find the common denominator, which will be 10000.
So we do:
2.2/1000 * 10/10 = 22/10000
9/10000 + 22/10000 = 31/10000 = 0.0031.
The sum of the weights of the two in insects is 0.0031 grams.
To find how much heavier the fly is than the gnat we do:
22/10000 - 9/10000 = 13/10000 = 0.0013
The fly is 0.0013 grams heavier than the gnat.
<em>The result can be shown in both exact and decimal forms.
</em>
<em>Exact Form:
</em>
<em>4
e
+
21
</em>
<em>Decimal Form:
</em>
<em>31.87312731
…</em>
Thanks,
<em>Deku ❤</em>
Answer:
79° is the measure of the required angle
since it is the vertically opposite angle of AOB.
