Answer:
50% probability that on a randomly selected day during this period, a unit of currency B was worth more than 1.094 units of currency A.
Step-by-step explanation:
The Empirical Rule(68-95-99.7 rule) states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 1.094
Standard deviation = 0.013
a) What is the probability that on a randomly selected day during this period, a unit of currency B was worth more than 1.094 units of currency A?
The normal distribution is symmetric, which means that 50% of the units of currency B are more than 1.094 of currency A and 50% are below.
So
50% probability that on a randomly selected day during this period, a unit of currency B was worth more than 1.094 units of currency A.
180.48 ft^2
Hope it’s right
Best luck with your studying
Answer:
im sure that the answer for box A=$600.6.
answer to option B.=107.5%
Answer:
y=1/3x+7/3
Step-by-step explanation:
y=mx+b where m=slope and b=y-intercept
m=(y2-y1)/(x2-x1)
m=(3-1)/(2-(-4))
m=2/(2+4)
m=2/6
simplify
m=1/3
y=1/3x+b
y-y1=m(x-x1)
y-1=1/3(x-(-4))
y-1=1/3(x+4)
y-1=1/3x+4/3
y=1/3x+4/3+1
y=1/3x+4/3+3/3
y=1/3x+7/3
