Let the least possible value of the smallest of 99 cosecutive integers be x and let the number whose cube is the sum be p, then
By substitution, we have that
and
.
Therefore, <span>the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube is 314.</span>
Answer:
R = 8.3144598 J. mol-1. K-1.
Step-by-step explanation:
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We are solving 6x6-4+9.
We will do three steps in this case.
First is 6x6, 6x6 is 30.
So now we must keep in our head we have 30 as our first number.
Now, let's -4 from 30. 30-4 is 26.
We just did step 2. Boom!
So, we have 26 as our second number. Let's do our third step.
If we have 26, we need to add 9 to that. To quickly find that we know that 26+10 is 36. That is adding ten, we need 9 so minus 1 from 36 we get 35.
Our final answer is 35.
Answer:
<h2>P = 60</h2>
Step-by-step explanation:
The formula of a distance between two points:
X(-3, -6), Y(21, -6). Substitute:
X(-3, -6), Z(21, 4). Substitute:
Y(21, -6), Z(21, 4). Substitute:
The perimeter of the triangle XYZ:
Substitute:
Answer:
B i think!
Step-by-step explanation:
