Help plzzzzzzz :)))))
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Answer:
Yes we can conclude.
Step-by-step explanation:
The sampling distribution of can be approximated as a Normal Distribution only if:
np and nq are both equal to or greater than 10. i.e.
- np ≥ 10
- nq ≥ 10
Both of these conditions must be met in order to approximate the sampling distribution of as Normal Distribution.
From the given data:
n = 50
p = 0.80
q = 1 - p = 1 - 0.80 = 0.20
np = 50(0.80) = 40
nq = 50(0.20) = 10
This means the conditions that np and nq must be equal to or greater than 10 is being satisfied. So, we can conclude that the sampling distribution of pˆ is approximately a normal distribution
Ok so you can see 2 triangles that i highlighted, flip it so it is the same direction as you can see from the drawing
using the similar triangle equation
you get
136/64 = x/136
cross multiply and get
64x=18496
x=289
hope it help
using the similar triangle equation
you get
136/64 = x/136
cross multiply and get
64x=18496
x=289
hope it help