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ki77a [65]
3 years ago
12

A pure lead bar 10 cm long is maintained with one end at T=300 K and the other at 310 K. The thermoelectric potential difference

thus induced across the ends is 12.8 ????V. Find the thermoelectric power for lead in this temperature range
Physics
1 answer:
dangina [55]3 years ago
7 0

Answer:1.28v/k

Explanation:

Thermoelectric power is the same as Seebeck coefficient.

So the formula is S =Vemf/Th - Tl

= 12.8/310-300

S= 12.8/10

=1.28V/T

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