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2 years ago

What current passes through a 1 kW heater with 25 V across it?

1 answer:

Ivan2 years ago

3 0

Answer:The voltage V in volts (V) is equal to the current I in amps (A) times the resistance R in ohms (Ω): V (V) = I (A) × R (Ω) The power P in watts (W) is equal to the voltage V in volts (V) times the current I in amps (A): P (W) = V (V) × I (A) AC Ohm's law calculator.

Explanation:

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Consider the following situations:

Snezhnost [94]

Answer:

Though no question is specified here but let analyzed experiences of each

Explanation:

1. Required a force to stop it (Law of inertial). Constant acceleration

2. will have reduced acceleration (deceleration)

3. Uniform acceleration may set in. it accelerate

4. maximized it speed since no friction affect it motion

5. accelerating. Vo=0 and V gradually increased

6. less or no friction opposes the motion

7. It experience reduce motion based on air friction

8. constant acceleration due to gravity

9. g can be a bit affected but still about equal

4 0

3 years ago

Should athletes be benched if their grades are too low, or should they be allowed to play anyway?

sdas [7]

They should be benched.

5 0

2 years ago

How much extra water does a 147-lb concrete canoe displace compared to an ultralightweight 38-lb kevlar canoe of the same size c

romanna [79]

We use the formula, to calculate the volume of water displaced by concrete canoe,

$V =\frac{W}{\gamma }$

Here, W is the weight of concrete canoe and $\gamma$ is the specific weight of water and its value is $62.4\ lb/ft^3$ .

So,

$V =\frac{ 147\ lb}{62.4\ lb/ft^3}=2.356\ ft^3$ .

Now the volume of water occupied in ultra lightweight kevlar canoe,

$v=\frac{w}{\gamma}$

Here, w is weight of kevlar canoe.

So,

$v=\frac{38\ lb}{62.4\ lb/ft^3} =0.6089\ ft^3$

Thus, the volume of water displaced,

$=V-v=2.356\ ft^3-0.6089\ ft^3=2.19\ ft^3$ .

Hence, the volume of water displaced canoe compared to an ultra-lightweight kevlar canoe is $2.19\ ft^3$

5 0

2 years ago

What is the mass of a 7.0 kilogram bowling ball on the surface of the moon?

babunello [35]

Answer:

1.16kg is the answer. Hope this helped

Explanation:

4 0

2 years ago

If the new moon happens on January 15th, what shape will it be on February 6th?

Jobisdone [24]

-- From January 15 to February 6 is a period of 22 days.

-- The period of the full cycle of moon phases is 29.53 days.

-- So those dates represent (22/29.53) = 74.5% of a full cycle of phases.

-- That's almost exactly 3/4 of a full cycle, so on February 6, the moon would be almost exactly at <em>Third Quarter</em>. That's the <em>left half of a disk </em>(viewed from the northern hemisphere).

3 0

3 years ago