2 years ago

Light waves reflect off the objects that you see. Where do those light waves originate?

1 answer:

3 0

Answer:

The Sun is a natural source for visible light waves and our eyes see the reflection of this sunlight off the objects around us.

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Need help guys please

goldenfox [79]

Answer:

6.378 * 10^6 m

Explanation:

Radius = 6378 km

Changing in metres

6378 km = 6378000 m

Now in scientific notation

= 6.378 * 10 ^ 6 m

5 0

3 years ago

Which celestial objects come in direct contact with earth

Lubov Fominskaja [6]

Answer:

Sun

Explanation:

Any asteroid in space is a celestial body. Classification of Celestial Bodies. A star is a form of a celestial object made up of a shining spheroid of plasma held together by its own gravity. The nearby star to Earth is the Sun.

8 0

3 years ago

If a change is made to a system in equilibrium, the equilibrium will shift to oppose the change.

Aleksandr [31]

Answer:

Explanation:

Because it won’t

5 0

3 years ago

Read 2 more answers

The particles of a gas are packed tightly together.

finlep [7]

Answer:

False

Explanation:

4 0

2 years ago

Read 2 more answers

Assume (unrealistically) that a TV station acts as a point source broadcasting isotropically at 3.2 MW. What is the intensity of

Dahasolnce [82]

Answer:

$I=1.5\times10^{-28}W/m^2$

Explanation:

The intensity is related to the power and surface area by $I=\frac{P}{A}=\frac{P}{4\pi r^2}$ . We need to calculate the surface area of a sphere of radius r=4.3ly.

Since 4.3ly is the distance light travels in 4.3 years at 299792458m/s, we can obtain it in meters by doing:

$r=vt=(299792458m/s)(4.3\times365\times24\times60\times60s)=4.1\times10^{16}m$

So we have:

$I=\frac{P}{4\pi r^2}=\frac{3.2\times10^6W}{4\pi (4.1\times10^{16}m)^2}=1.5\times10^{-28}W/m^2$

4 0

3 years ago