Answer: No, x+3 is not a factor of 2x^2-2x-12
========================================================
Explanation:
Let p(x) = 2x^2 - 2x - 12
If we divide p(x) over (x-k), then the remainder is p(k). I'm using the remainder theorem. A special case of the remainder theorem is that if p(k) = 0, then x-k is a factor of p(x).
Compare x+3 = x-(-3) to x-k to find that k = -3.
Plug x = -3 into the function
p(x) = 2x^2 - 2x - 12
p(-3) = 2(-3)^2 - 2(-3) - 12
p(-3) = 12
We don't get 0 as a result so x+3 is not a factor of p(x) = 2x^2 - 2x - 12
----------------------------------------
Let's see what happens when we factor p(x)
2x^2 - 2x - 12
2(x^2 - x - 6)
2(x - 3)(x + 2)
The factors here are 2, x-3 and x+2
Answer:
There are 4 terms
Step-by-step explanation:
A term is a single mathematical expression. Terms can be identified with a plus or minus sign in front of them. Terms can also be multiplied and divided.
So, in this case, the terms are:
-7
12x^4
-5y^8
x
86, 90, and 92
Explanation:add all numbers together and divide it by the amount of numbers there are (5) and it comes out with 85.6 so it has to be higher since it increased
Answer:61
Step-by-step explanation:
Its common logic
10 is greater because it equals 3.162...
