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tamaranim1 [39]
4 years ago
14

Why are changes in the global carbon cycle important? I) Burning reduces available carbon for primary producers and, therefore,

primary consumers. II) Deforestation and suburbanization reduce an area's rate at which energy is stored as biomass by plants or other primary producers and made available to the consumers in the ecosystem. III) Increasing atmospheric concentrations of carbon dioxide could alter Earth's climate.
Chemistry
1 answer:
mr Goodwill [35]4 years ago
7 0

Answer:

iii) Increasing atmospheric concentrations of carbon dioxide could alter Earth's climate

Explanation:

Increased concentration of carbon dioxide traps heat in the earth or insulate the Earth leading to increase in temperature of the Earth. Example of the effect is retreating polar ice caps as a result of melting. Having an understanding of the release and absorption of carbon dioxide, one of the green house gases,  is important to predict global warming trends and understand the climate. Other examples of green houses gas include water vapor, methane, CFC, nitrous oxide and others

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1. An unknown amount of mercury (II) oxide was decomposed in the lab. Mercury metal was formed and 4.50 L of oxygen gas was rele
Musya8 [376]

Answer:

1. 59.1 g HgO

2. A.) 38.2 L

3. B.) It is directly proportional to the number of moles of the gas.

Step-by-step explanation:

1. Mass of HgO

We know we will need a chemical equation with masses and molar masses, so let's gather all the information in one place.

M_r:   216.59

          2HgO ⟶ 2Hg + O₂

(a) Calculate the <em>moles of O₂</em>  

pV = nRT            Divide each side by RT  

 n = (pV)/(RT)  

<em>Data: </em>

p = 0.970 atm  

V = 4.50 L  

R = 0.082 06 L·atm·K⁻¹mol⁻¹  

T = 390.0 K  

<em>Calculation: </em>

n = (0.970 × 4.500)/(0.082 06 × 390.0)  

n = 0.1364 mol O₂

(b) Calculate the <em>moles of HgO </em>

The molar ratio is 1 mol O₂/2 mol HgO.

Moles of HgO = 0.1364 mol O₂ × (2 mol Hg/1 mol O₂)

Moles of HgO = 0.2728 mol HgO

(c) Calculate the <em>mass of HgO </em>

Mass of HgO = 0.2728 mol HgO × (216.59 g HgO/1 mol HgO)

Mass of HgO = <em>59.1 g HgO</em>

This isn't any of the options in your list. Have I made an error?

2. Volume of Hydrogen

              Mg + 2HCl ⟶ MgCl₂ + H₂

n/mol:              3.00

(a) Calculate the <em>moles of H₂ </em>

The molar ratio is (1 mol H₂/2 mol HCl).

Moles of H₂ = 3.00 mol HCl × (1 mol H₂/2 mol HCl)

Moles of H₂ = 1.50 mol HCl

(b) Calculate the <em>volume of H₂ </em>

pV = nRT     Divide both sides by p

 V = (nRT)/p

<em>Data: </em>

n = 1.50 mol

T = 298 K

p = 0.960 atm

<em>Calculation: </em>

V = (1.5 × 0.082 06 × 298)/0.960

V = 38.2 L

3. Volume of gas

pV = nRT

 V = nRT/p

If T and p are constant, (RT)/p = constant = k

V = kn

V ∝ n

The volume is directly proportional to the number of moles of the gas.

3 0
4 years ago
14. I have an unknown volume of gas at a pressure of 1.2 atm and a temperature of 210 K. If I raise the pressure to 1.9 atm and
Leya [2.2K]

Answer:

The law is given by the following equation: PV = nRT, where P = pressure, V = volume, n = number of moles, R is the universal gas constant, which equals 0.0821 L-atm / mole-K, and T is the temperature in Kelvin.

Explanation:

6 0
3 years ago
Calculate the amount of heat gained by the water in cup 2 after adding the hot object(s) to it.
Iteru [2.4K]

Answer:

The amount of heat gained by the water in cup 2 after adding the hot object(s) to it is 2119.121 Joules

Explanation:

As we know

Amount of heat gained

Q = mc (T2-T1)

Here,

mass of water in cup 2 (m) = 79.10 grams

Temperature of water in cup 2 = 16.8 degree Celsius

Specific heat of water (c) = 4.186 J/(g °C)

Final Temperature of water in cup 2  = 23.2 degree Celsius

Substituting the given values, we get -

Q = 79.10 * 4.186 * (23.2 -16.8) = 2119.121 Joules

The amount of heat gained by the water in cup 2 after adding the hot object(s) to it is 2119.121 Joules

3 0
3 years ago
Which of the following statements is true?
Hitman42 [59]
I guess its D.hope this helps....sorry if i'm wrong.
5 0
3 years ago
Read 2 more answers
A canister of neon contains 4.8x1024 atoms of the gas. How many moles of neon are present in the canister?
algol [13]

Answer:

7.97 moles of neon are present in the canister.

Explanation:

Avogadro's constant or "Avogadro's number" is the number of constituent particles found in the amount of substance in one mole.

In other words, Avogadro's number is the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number applies to any substance.

So, you can apply the following rule of three: if 6.023*10²³ atoms are present in 1 mole, 4.8*10²⁴ atoms are present in how many moles?

amount of moles=\frac{4.8*10^{24}atoms*1 mole }{6.023*10^{23}atoms}

amount of moles= 7.97 moles

<u><em>7.97 moles of neon are present in the canister.</em></u>

4 0
3 years ago
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