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Jlenok [28]
3 years ago
8

1) How does the frequency of sound affect the speed of sound?

Physics
1 answer:
Travka [436]3 years ago
5 0

Changing frequency of sound does not change the speed of the sound.

Explanation:

  • Speed of the sound gets altered when the sound travels from one medium to another.
  • Change in frequency does not affect the speed of the sound and speed is affected by the properties of the medium through which it travels.
  • Therefore, to change the speed of the sound, the properties of the medium needs to be changed.

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Two resistors, of R1 = 3.93 Ω and R2 = 5.59 Ω, are connected in series to a battery with an EMF of 24.0 V and negligible interna
son4ous [18]

Answer:

2.521 (A); 14.0924 (V)

Explanation:

more info in the attachment, the answers are marked with red colour.

4 0
3 years ago
Recycled plastics cannot be used to produce new food containers because ___
Lena [83]

they cannot be sterilized

4 0
4 years ago
What types of cells are likely to have lots of smooth ER?
Andrei [34K]

Answer:

eukaryotic cells

Explanation:

"Smooth endoplasmic reticulum (sER) is (a part of) endoplasmic reticulum that is tubular in form and lacks ribosomes. It is present in eukaryotic cells and is associated with lipid synthesis, carbohydrate metabolism, regulation of calcium concentration, and drug detoxification"

source: biologyonline

8 0
3 years ago
A wheel starts from rest and rotates with constant angular acceleration to reach an angular speed of 11.1 rad/s in 2.99 s.(a) fi
elena55 [62]
The angular acceleration of a rotating object is given by
\alpha =  \frac{\omega_f - \omega_i}{\Delta t}
where
\omega_f is the final angular speed of the object
\omega_i is its initial angular speed
\Delta t is the time taken to accelerate

For the wheel in our problem, \omega_f=11.1 rad/s, \omega_i = 0 and \Delta t=2.99 s, so its angular acceleration is
\alpha= \frac{11.1 rad/s-0}{2.99 s}=3.71 rad/s^2
8 0
3 years ago
An observer stands 24.7 m behind a marksman practicing at a rifle range. The marksman fires the rifle horizontally, the speed of
GaryK [48]

Explanation:

The given data is as follows.

     Velocity of bullet, c_{p} = 814.8 m/s

    Observer distance from marksman, d = 24.7 m

Let us assume that time necessary for report of rifle to reach the observer is t and will be calculated as follows.

               t = \frac{24.7}{343}      (velocity in air = 343 m/s)

                 = 0.072 sec

Now, before the observer hears the report the distance traveled by the bullet is as follows.

               d_{b} = c_{b} \times t

                          = 814.8 \times 0.072

                          = 58.66

                          = 59 (approx)

Thus, we can conclude that each bullet will travel a distance of 59 m.

8 0
3 years ago
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