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3 years ago

Ok plz answer and tell me how to do it

Physics

1 answer:

kirza4 [7]3 years ago

4 0

Answer: 25N

method: total force in the right hand direction is 100N and total force in the left hand direction is 125N. To get the net force, we add forces if they are in the same direction and substract if they are in opposite directions. since 100N and 125N are in opposite directions, we substract the larger value from the smaller value. Then we get 25N in the left hand direction as the final answer.

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3 years ago

When the distance between two objects doubles, what happens to the gravitational attraction between these two objects?

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Answer:

As indicated by Newton's law of attraction each article or body in the universe draws in every single item towards one another and that power of fascination is straightforwardly relative to the result of their masses and contrarily corresponding to the square of the distance between them.

The power of gravity between two articles will diminish as the distance between them increments. The two most significant elements influencing the gravitational power between two items are their mass and the distance between their focuses. As mass increments, so does the power of gravity, however an increment in distance mirrors a reverse proportionality, which makes that power decline dramatically.

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3 years ago

A certain freely falling object, released from rest, requires 1.50 s to travel the last 30.0 m before it hits the ground. From w

BaLLatris [955]

Answer:

The object fell from about 38.14 meters

Explanation:

We can use the formula for displacement under accelerated motion due to gravity to find the velocity of the object had 30 m before hitting the ground :

$y_f-y_i=v_i * \,t-\frac{9.8}{2} \,t^2\\0-30=v_i \,(1.5)-4.9\,(1.5)^2\\-18.975=v_i\,(1.5)\\v_i=-12.65\,\,\frac{m}{s}$

Now, knowing this velocity, we can find the time it took to fall from the initial position to 30 m before hitting the ground:

$v_f=v_i-g\,*\,t\\-12.65=0-g \,*\,t\\t=\frac{12.65}{g} \\t\approx1.29\,\,s$

And now we can find what is the total distance covered in 1.5 s plus 1.29 seconds for this free falling object:

$y_f-y_i=v_i * \,t-\frac{9.8}{2} \,t^2\\0-y_i=0-\frac{9.8}{2} \,(2.79)^2\\-y_i=-38.14\\y_i=38.14\,\,m$

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3 years ago

A hypothetical planet has a mass one-third of and a radius three times that of Earth. What is the acceleration due to gravity on

kap26 [50]

Answer:

F) The acceleration due to gravity is g/27

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According to Newton gravitational law, the gravitational acceleration is directly proportional to the planet mass and inversely proportional to the square of distance.

Since our new planet has a mass of one-third of Earth's and radius 3 times of Earth's. This means the new planet is lighter and further away from the distance. This means g is first reduced by 3 due to smaller mass and then reduced by 9 due to square of 3 times the distance.

The gravitational acceleration on this new planet must be

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3 years ago