An uncharged body is a body that has equal magnitude of positive as well as negative charge on it. So as soon as some charged body is placed near it, the charged body induces negative charges on the uncharged body.
D) decreases, inverse
Explanation:
The average speed of each lap decreases. This is an example of an inverse relationship.
Speed is the rate of change of distance with time. In calculating the average speed, we should understand that the total length of path is taken into consideration and so is the total time taken.
Average speed = 
It was explained that after every 5 seconds the speed of the runner becomes slower.
There is definitely an inverse relationship between average speed and the total time taken.
An inverse relationship is such that as one variable increases, the other diminishes.
As average speed reduces the time taken increases.
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The maximum height reached by the ball during the upward motion is 24.7 m.
The given parameters;
- <em>initial velocity of the ball, u = 22 m/s</em>
The maximum height reached by the ball is determined using the third kinematic equation as shown below;
v² = u² - 2gh
where;
- <em>v is the </em><em>final velocity </em><em>of the ball at the maximum height = </em><em>0</em>
- <em>h is the maximum height attained by the ball</em>
0 = u² - 2gh
2gh = u²

Thus, the maximum height reached by the ball during the upward motion is 24.7 m.
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Beta Decay takes place. During beta decay, the beta particle is produced when a Neutron changes into a proton and an electron. Beta decay<span> (</span>β-decay<span>) is a type of </span>radioactive decay<span> in which a </span>beta<span> ray and a neutrino are emitted from an atomic nucleus. Neither the </span>beta particle<span> nor its associated neutrino exist within the nucleus prior to </span>beta decay<span>, but are created in the </span>decay process<span>.</span>
Answer:

Explanation:
For this case we can use the following formula for the angular velocity:

where
represent the final angular velocity ,
the initial angular velocity , t the time and
the angular acceleration.
And for the linear acceleration we have this formula:

Where a represent the linear acceleration and
the angular acceleration.
For this case the linear acceeleration is given 
And the radius of the yo-yo is also given 
So then we can use the following formula:

If we replace the values we got:

And solving for
we got:
