Question

Catherine is creating a triangular banner for her school's football team. She wants the height of the banner to be 4 times as tall as the width of the base of the triangle. If she wants the total area of the banner to be 8 feet squared (8ft2), how wide should the base of the triangle be in feet?

Answer 1

Answer:

The base of the triangle should be 2 feet

Step-by-step explanation:

Let the base of the triangle be y  

She wants the height of the banner to be 4 times as tall as the width of the base of the triangle

So height  is  =  $4 \times y$ = 4y

Now we know that the area of the triangle is  =$\frac{1}{2} (base \times height)$

we  also know that total area of the banner is 8 feet squared

Then

$8 = \frac{1}{2}(y \times 4y)$

$8 = \frac{4y^2}{2}$

$16 = 4y^2$

$\frac{16}{4} = y^2$

$4 = y^2$

$y = \sqrt{4}$

y = 2

Width if the base of the triangle is 2 feet