Answer:
Following are the program in the Python Programming Language:
#set dictionary
d = { 'State' : 'Delhi', 'Country' : 'India'};
#reverse the dictionary.
revers = dict((v, k) for k, v in d.items())
#Displays the reversed dictionary.
print("Dictionary is: \n")
print(revers)
<u>Output</u>:
Dictionary is:
{'Delhi': 'State', 'India': 'Country'}
Explanation:
Here, we set the dictionary data type variable "d" then, we set the variable in which we store the reverse of the dictionary in which key is converted into the value and value is converted into the key. and finally we print the reverse dictionary.
Answer:
result = 0
i = lo
while i <= hi:
result = result + i
i += 1
Explanation:
Initialize the <em>result</em> as 0 to hold the summation value.
Since we are asked not to change the value of <em>lo</em> and <em>hi</em>, our loop control variable is <em>i</em> and initially it starts from <em>lo.</em>
Since we are asked to add the number from <em>lo</em> to <em>hi, </em>while loop condition checks it.
While the condition satisfies (during each iteration), the value of <em>i</em> is added to the result and the value of <em>i</em> is incremented by one.
Answer:
#include <bits/stdc++.h>
using namespace std;
bool isPrime(int n)
{
for(int j=2;j<=n-1;j++) //loop to check prime..
{
if(n%j==0)
return false;
}
return true;
}
int main(){
int n;
cout<<"Enter the integer"<<endl;//taking input..
cin>>n;
if(isPrime(n))//printing the message.
{
cout<<"The number you have entered is prime"<<endl;
}
else
{
cout<<"The number is not prime"<<endl;
}
return 0;
}
Output:-
Enter the integer
13
The number you have entered is prime
Explanation:
The above written program is in C++.I have created a function called isPrime with an argument n.I have used a for loop to check if the number is prime or not.In the main function I have called the function isPrime for checking the number is prime or not.
