Answer:
-18
Step-by-step explanation:
Hope it helps....................................................
Answer: ![-\frac{8}{77}](https://tex.z-dn.net/?f=-%5Cfrac%7B8%7D%7B77%7D)
Step-by-step explanation:
![\frac{\frac{4}{7} }{-\frac{11}{2} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cfrac%7B4%7D%7B7%7D%20%7D%7B-%5Cfrac%7B11%7D%7B2%7D%20%7D)
Multiply by the reciprocal in order to get rid of the fraction in the denominator.
![\frac{\frac{4}{7} }{-\frac{11}{2} }*-\frac{2}{11}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cfrac%7B4%7D%7B7%7D%20%7D%7B-%5Cfrac%7B11%7D%7B2%7D%20%7D%2A-%5Cfrac%7B2%7D%7B11%7D)
![\frac{4}{7}*-\frac{2}{11}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B7%7D%2A-%5Cfrac%7B2%7D%7B11%7D)
![-\frac{8}{77}](https://tex.z-dn.net/?f=-%5Cfrac%7B8%7D%7B77%7D)
Answer: No
Step-by-step explanation:
To get the least possible product, you want both the 2-digit number and the 1-digit number to be as small as possible
The smallest 2-digit number is 10
The smallest nonzero 1-digit number is 1
so the smallest product is 10 * 1 = 10
What I would do here is substitute "5y -87" for x in the first ecquation, since the second equation is already in the form "x=..." so:
4*(5y-87)+9y=29
getting rid of the bracket:
20y-348+9y=29
adding up:
29y=29+348
29y= 377
dividing by 29:
y=13
and now we can calculate x, which is 5*13-87=65-87=-22
so x=-22