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3 years ago

PLZ HELP :((( if i get an 80 or lower am going to fail....

Mathematics

2 answers:

pav-90 [236]3 years ago

8 0

Answer: Listen u are right on 1 and 2 don’t know about 3 but Um the website is incorrect u had 1 and 2 correct so I don’t know

Step-by-step explanation:

ehidna [41]3 years ago

5 0

Answer:

1.) 22

2.) 122

Step-by-step explanation:

For the first 1, the degrees in a right angle is 90 degrees and if you already have 68 you have to subtract 90-68= 22.

For the second one, an obtuse angle is 180 degrees. If you already have 58 degrees so you have to subtract 180-58= 122 degrees.

The reason you are subtracting is to find the remaining numbers.

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Solve the matrix equation for a, b, c, and d. [1 2] [a b] [6 5][3 4] [c d]= [19 8]

Anit [1.1K]

Answer:

The answer is " $\bold{\left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}7&-2\\ -\frac{1}{2}&\frac{7}{2}\end{array}\right]}$ ".

Step-by-step explanation:

$\bold{\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}6&5\\ 19&8\end{array}\right]}$

Solve the L.H.S part:

$\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}a&b\\c&d\end{array}\right]\\\\\\\left[\begin{array}{cc}a+2c&b+2d\\3a+4c&3b+4d\end{array}\right]$

After calculating the L.H.S part compare the value with R.H.S:

$\left[\begin{array}{cc}a+2c&b+2d\\3a+4c&3b+4d\end{array}\right]= \left[\begin{array}{cc}6&5\\ 19&8\end{array}\right]} \\\\$

$\to a+2c =6....(i)\\\\\to b+2d =5....(ii)\\\\\to 3a+4c =19....(iii)\\\\\to 3b+4d = 8 ....(iv)\\\\$

In equation (i) multiply by 3 and subtract by equation (iii):

$\to 3a+6c=18\\\to 3a+4c=19\\\\\text{subtract}... \\\\\to 2c = -1\\\\\to c= - \frac{1}{2}$

put the value of c in equation (i):

$\to a+ 2 (- \frac{1}{2})=6\\\\\to a- 2 \times \frac{1}{2}=6\\\\\to a- 1=6\\\\\to a =6 +1\\\\\to a = 7\\$

In equation (ii) multiply by 3 then subtract by equation (iv):

$\to 3b+6d=15\\\to 3b+4d=8\\\\\text{subtract...}\\\\\to 2d = 7\\\\\to d= \frac{7}{2}\\$

put the value of d in equation (iv):

$\to 3b+4 (\frac{7}{2})=8\\\\\to 3b+4 \times \frac{7}{2}=8\\\\\to 3b+14=8\\\\\to 3b =8-14\\\\\to 3b = -6\\\\\to b= \frac{-6}{3}\\\\\to b= -2$

The final answer is " $\bold{\left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}7&-2\\ -\frac{1}{2}&\frac{7}{2}\end{array}\right]}$ ".

4 0

3 years ago

Can you help me with the first two questions?

melisa1 [442]

$1.\\\$55\ 000-\$1\ 000=\$54\ 000\\\\\$54\ 000:2=\$27\ 000\\\\\\Answer:B$

$2.\\-4(x-11)=16\\\\-4\cdot x-4\cdot(-11)=16\\\\-4x+44=16\ \ \ /:(-4)\\\\-4x:(-4)+44:(-4)=16:(-4)\\\\x-11=-4\\\\Answer:G$

7 0

3 years ago

Read 2 more answers

Use Newton's method to approximate a root of the equation 3x^7+2x^4+3=0 Let x1 =1 be the initial approximation. The second appro

liubo4ka [24]

Answer:

3.3

Step-by-step explanation:

logging in and answering

5 0

3 years ago

Someone help please ://////

GarryVolchara [31]

Answer:

+/- 1.5

Step-by-step explanation:

3 0

3 years ago

The ratio of runners to swimmers was 3:2. When 28 runners dropped out of the competition, the ratio became 5:6. How many total s

xz_007 [3.2K]

The total of 42 swimmers are competing

Step-by-step explanation:

The given is:

The ratio of runners to swimmers was 3 : 2
When 28 runners dropped out of the competition, the ratio became 5 : 6

We need to find how many total swimmers are competing

∵ The ratio of runners to swimmers was 3 : 2

- Multiply each term of the ratio by x

∴ There are 3x runners and 2x swimmers

∵ 28 runners dropped out of the competition

∴ The number of runners who complete = 3x - 28

∵ The ratio became 5 : 6

- Equate the ratio between the new number of runners and the

number of swimmers by 5 : 6

∵ The new number of runners = 3x - 28

∵ The number of swimmers = 2x

∴ $\frac{3x-28}{2x}=\frac{5}{6}$

- By using cross multiplication

∴ 6(3x - 28) = 5(2x)

- Simplify both sides

∴ 18x - 168 = 10x

- Add 168 to both sides

∴ 18x = 10x + 168

- Subtract 10x from both sides

∴ 8x = 168

- Divide both sides by 8

∴ x = 21

∵ The number of swimmers is 2x

∵ x = 21

∴ The number of swimmers = 2(21) = 42

The total of 42 swimmers are competing

Learn more:

You can learn more about the ratio in brainly.com/question/2707032

#LearnwithBrainly

7 0

3 years ago