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mr_godi [17]
2 years ago
8

Consider angle θ in Quadrant ll, where cos θ= -12/13. what's the value of sin θ​

Mathematics
1 answer:
Bas_tet [7]2 years ago
6 0

Answer:

sinθ = 5/13

Step-by-step explanation:

cosθ​ = adjacent/hypotenuse (or you could think of it as x/r)

cosθ = -12/13

adjacent = -12

hypotenuse = 13

opposite = ?

To get the opposite, we use the Pythagorean theorem

hypotenuse^{2} = adjacent^{2}  + opposite^2

hypotenuse^{2} - adjacent^{2}  = opposite^2

\sqrt(hypotenuse^{2} - adjacent^{2})  = opposite

Now sub in the numbers:

\sqrt{(13^2 - (-12)^2)} = opposite

opposite = 5

Now sinθ = opposite/hypotenuse

so sinθ = 5/13

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I hope this helps. =)

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