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mr_godi [17]
2 years ago
8

Consider angle θ in Quadrant ll, where cos θ= -12/13. what's the value of sin θ​

Mathematics
1 answer:
Bas_tet [7]2 years ago
6 0

Answer:

sinθ = 5/13

Step-by-step explanation:

cosθ​ = adjacent/hypotenuse (or you could think of it as x/r)

cosθ = -12/13

adjacent = -12

hypotenuse = 13

opposite = ?

To get the opposite, we use the Pythagorean theorem

hypotenuse^{2} = adjacent^{2}  + opposite^2

hypotenuse^{2} - adjacent^{2}  = opposite^2

\sqrt(hypotenuse^{2} - adjacent^{2})  = opposite

Now sub in the numbers:

\sqrt{(13^2 - (-12)^2)} = opposite

opposite = 5

Now sinθ = opposite/hypotenuse

so sinθ = 5/13

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compute the projection of → a onto → b and the vector component of → a orthogonal to → b . give exact answers.
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\text { Saclar projection } \frac{1}{\sqrt{3}} \text { and Vector projection } \frac{1}{3}(\hat{i}+\hat{j}+\hat{k})

We have been given two vectors $\vec{a}$ and $\vec{b}$, we are to find out the scalar and vector projection of $\vec{b}$ onto $\vec{a}$

we have $\vec{a}=\hat{i}+\hat{j}+\hat{k}$ and $\vec{b}=\hat{i}-\hat{j}+\hat{k}$

The scalar projection of$\vec{b}$onto $\vec{a}$means the magnitude of the resolved component of $\vec{b}$ the direction of $\vec{a}$ and is given by

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$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|}$

$$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\sqrt{1^2+1^1+1^2}} \\&=\frac{1^2-1^2+1^2}{\sqrt{3}}=\frac{1}{\sqrt{3}}\end{aligned}$$

The Vector projection of $\vec{b}$ onto $\vec{a}$ means the resolved component of $\vec{b}$ in the direction of $\vec{a}$ and is given by

The vector projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|^2} \cdot(\hat{i}+\hat{j}+\hat{k})$

$$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\left(\sqrt{1^2+1^1+1^2}\right)^2} \cdot(\hat{i}+\hat{j}+\hat{k}) \\&=\frac{1^2-1^2+1^2}{3} \cdot(\hat{i}+\hat{j}+\hat{k})=\frac{1}{3}(\hat{i}+\hat{j}+\hat{k})\end{aligned}$$

To learn more about scalar and vector projection visit:brainly.com/question/21925479

#SPJ4

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