All categories

3 years ago

Multiplying an odd number of negative numbers gives an answer that is

Mathematics

1 answer:

nata0808 [166]3 years ago

7 0

Answer:

even or odd it depends

Step-by-step explanation:

I dont know I will give you some points

You might be interested in

The probability distribution of the amount of memory X (GB) in a purchased flash drive is given below. x 1 2 4 8 16 p(x) .05 .10

Rama09 [41]

Answer:

a) $E(X) = 6.45$

b) $E(X^{2} )= 57.25$

c) $V(X) = 15.648$

d) E(3X + 2) = 21.35

e) $E(3X^{2} +2) = 173.75$

f) V(3X+2) = 140.832

g) E(X+1) = 7.45

h) V(X+1) = 15.648

Step-by-step explanation:

a) $E(X) = \sum xP(x)$

$E(X) = (1*0.05) + (2*0.10) + (4*0.35) + (8*0.40) + (16*0.10)\\E(X) = 6.45$

$E(X^{2} ) = (1^{2} *0.05) + (2^{2} *0.10) + (4^{2} *0.35) + (8^{2} *0.40) + (16^{2} *0.10)\\ E(X^{2} )= 57.25$

$V(X) = E(X^{2} ) - (E(X))^{2} \\V(X) = 57.25 - 6.45^{2} \\V(X) = 15.648$

$E(3X+2) = 3E(X) + 2\\E(3X+2) = (3*6.45) + 2 \\E(3X+2) = 21.35$

$E(3X^{2} +2) = 3E(X^{2} ) + 2\\E(3X^{2} +2) = (3*57.25) + 2 \\E(3X^{2} +2) = 173.75$

$V(3X+2) = 3^{2} V(X)\\V(3X+2) = 9*15.648\\V(3X+2) = 140.832$

$E(X+1) = E(X) + 1\\E(X+1) = 6.45 + 1\\E(X+1) =7.45$

$V(X+1) = 1^{2} V(X)\\V(X+1) = 15.648$

6 0

3 years ago

Evaluate the expression when c=-6

Afina-wow [57]

Answer:

Hi how are you

Step-by-step explanation:

Have a nice day

8 0

3 years ago

What two factors of 25 also have the sum of -10?

Andrews [41]

Answer:

-5 and -5.

Step-by-step explanation:

Two negative numbers multiply to make a positive and add to make a negative.

4 0

2 years ago

Please answer this correctly

pickupchik [31]

Answer:

66.7%

Step-by-step explanation:

The factors of 18 are as listed: 1, 2, 3, 6, 9, 18

Since 1, 2, 3, and 6 are in the die, that makes 4 out of the 6 numbers.

4/6 can be simplified to .667 or 66.7%

4 0

3 years ago

Read 2 more answers

Write as many equivalent forms as you can. HELPPPPPPPPPPPP

ANTONII [103]

$\frac{1}{ {(3k)}^{ \frac{5}{2} } } = {(3k)}^{ - \frac{5}{2} } \\ = \frac{1}{( { \sqrt{3k}) }^{5} } = ({ \sqrt{3k} })^{ - 5}$

5 0

3 years ago