All categories

2 years ago

3. Starbucks Coffee was selling for $57.12 per share eighteen months ago and you

Mathematics

1 answer:

Makovka662 [10]2 years ago

3 0

Answer: 120.5 shares

Step-by-step explanation: You add 68.38 and 57.12 and there is you answer

You might be interested in

A rectangle's width is twice as long as its length. If the perimeter is 36 in., what is the length?

Bumek [7]

Okay here:

Let L be the length and W the width of the rectangle.

1. w=2•L
2. 2L+2W=36

Substitute eq. 1 into eq. 2,

2L+2•(2•L)=36

2L+4L=36

6L=36

L=9

Not done yet, then from eq. 1,

W=2•L
W=2•9
W=18 <------- Your answer. :)

6 0

2 years ago

Simplify. <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%5C%5C%7D" id="TexFormula1" title="\frac{1}{2\\}" alt="\fra

topjm [15]

1/2d*12d
1*d*12d/2
12d^2/2
6d^2

4 0

1 year ago

Read 2 more answers

If x = -6,which inequiality is true

zimovet [89]

The only equation that works with x=-6 is A

7 0

2 years ago

Sabrina threw a coin from a building 160 feet high at an initial speed of 30 feet per second. How many seconds will it take the

nirvana33 [79]

Without speeding up it would take 5 1/3 seconds.. not sure if it speeds up in the question?

3 0

2 years ago

Security A rounds every 2 minutes and 20 seconds in the gate 1. Security B rounds every 1 minute and 40 seconds in the gate 2. I

Elden [556K]

Answer:

$Time = 11\frac{2}{3}\ min$

Step-by-step explanation:

Given

$Security\ A = 2\ mins, 20\ secs$

$Security\ B = 1\ mins, 40\ secs$

Required

After how many minutes, will they round together

First, convert the given time to minutes

$Security\ A = 2\ mins, 20\ secs$

$Security\ A = 2\ mins+ 20\ secs$

$Security\ A = 2\ mins+ \frac{20}{60}\ min$

$Security\ A = 2\ mins+ \frac{1}{3}\ min$

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\ mins, 40\ secs$

$Security\ B = 1\ mins+ 40\ secs$

$Security\ B = 1\ mins+ \frac{40}{60}\ min$

$Security\ B = 1\frac{2}{3}\ min$

So, we have:

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\frac{2}{3}\ min$

List out the multiples of the time of both security personnel take round.

$Security\ A = 2\frac{1}{3}min,\ 4\frac{2}{3}min,\ 7min,\ 9\frac{1}{3}min,\ 11\frac{2}{3}min...$

$Security\ B = 1\frac{2}{3}min,\ 3\frac{1}{3}min,\ 5min,\ 6\frac{2}{3}min,\ 8\frac{1}{3}min,\ 10min\ ,11\frac{2}{3}min,...$

In the above lists, the common time is:

$Time = 11\frac{2}{3}\ min$

This implies that they go on round after $11\frac{2}{3}\ min$

4 0

2 years ago