3 years ago

Can anyone help me with #1? It has two answers...

Mathematics

1 answer:

Verizon [17]3 years ago

5 0

Answer:

√-16=4√-1=4i

4i is an imaginary number and a complex number.

You might be interested in

16 paise into rupees

denis-greek [22]

Answer:

0.16

Step-by-step explanation:

1paise = 1/100rupee

so, 16 paise = 16/100

16/100= 0.16

7 0

2 years ago

Hey Hey :-)<br> ^^^^^^^^^^^

Annette [7]

Answer:

50.27 or 16pi

Step-by-step explanation:

Just multiply the diameter by pi

3 0

3 years ago

Read 2 more answers

Find the length of AB.

alexdok [17]

Jdjdjjddjdjdjjdjdjdjd

4 0

3 years ago

Someone plz help because I am using my last amount of points and I don't want it to be wasted from no answer.I need help with qu

ser-zykov [4K]

Wheres the questions???

7 0

2 years ago

During the period from 1790 to 1930, the US population P(t) (t in years) grew from 3.9 million to 123.2 million. Throughout this

alex41 [277]

Answer:

Step-by-step explanation:

Given that during the period from 1790 to 1930, the US population P(t) (t in years) grew from 3.9 million to 123.2 million. Throughout this period, P(t) remained close to the solution of the initial value problem.

$\frac{dP}{dt} =0.03135P =0.0001489P^2, P(0) = 3.9$

a) 1930 population is the population at time t = 40 years taking base year as 40

We can solve the differential equation using separation of variables

$\frac{dP}{0.03135P – 0.0001489P^2 } =dt\\\frac{dP}{-P(0.03135 – 0.0001489P } =dt$

Resolve into partial fractions

$\frac{31.8979}{P} -\frac{0.00474}{0.0001489P-0.03135}$

Integrate to get

ln P -0.00474/0.0001489 (ln (0.0001489P-0.03135) = t+C

ln P -31.833 (ln (0.0001489P-0.03135) =t+C

$\frac{P}{( ( (0.0001489P-0.03135)^{31.833} } =Ae^t$

Limiting population would be infinity.

6 0

3 years ago