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Evgesh-ka [11]
4 years ago
10

Find all the real cube roots of each number. -64

Mathematics
2 answers:
masya89 [10]4 years ago
4 0
The cubed root of -64 is -4.

-4*-4*-4=-64
Masteriza [31]4 years ago
3 0

Every number has three cube roots.

The only real cube root of -64 is <em>-4</em> .

The other two cube roots of -64 are a pair of complex conjugates.
I'm too lazy to calculate them right now, and you didn't ask for them
anyway.


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3 years ago
(57x2:3)+32x450-[39-(4+2):2[+8=
tigry1 [53]

Answer:

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8 0
2 years ago
Simplify the given expression below: (7-3i)•(2-i)
Dimas [21]

when multiplying two binomials together we use the F.O.I.L. method:

First

Outer

Inner

Last

(7-3i)(2-i)

First: 7 * 2 ..... Outter: 7 * -i .... Inner: -3i * 2 ...... Last: -3i * -i

First: 14 ...... Outter= -7i ..... Inner: -6i .... Last: 3i^2

putting this together we get 14-7i-6i+2i^2

We combine like terms and end up with 2i^2-13i+14

5 0
3 years ago
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sergiy2304 [10]
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4 0
3 years ago
WILL MARK BRAINLIEST
Ivanshal [37]

Answer:

27

Step-by-step explanation:

First you need to find x.

It is shown that DE=EF, so we can use this.

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x=5

Then, you plug in the value of the variable and solve.

6(5)-3

30-3

27 = DF

8 0
3 years ago
Read 2 more answers
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